Java 为 class.getResource() 定义根类路径
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/19104545/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
defining root classpath for class.getResource()
提问by user1028741
I'm using java in Eclipse (windows), and I'm trying to use:
我在 Eclipse (windows) 中使用 java,我正在尝试使用:
myClass.getResource("/image.jpg"),
While image.jpg exists in the root loacation "myProject/". It returns null.
而 image.jpg 存在于根位置“myProject/”中。它返回空值。
I checked many other threads but none of them resolved my issue.
我检查了许多其他线程,但没有一个解决了我的问题。
So I tried to evaluate this:
所以我试图评估这一点:
this.getClass().getResource("/").getPath();
and it returned "myProject/build/classes".
它返回了“myProject/build/classes”。
So I checked the project's configuration for this dir, and found the exact same dir under
所以我检查了这个目录的项目配置,并在下面找到了完全相同的目录
Java Build Path --> Source --> Default output folder
Java 构建路径 --> 源 --> 默认输出文件夹
My questions are:
我的问题是:
why is the default dir of my resources is the output folder?
As mentioned, I want to get a resource from another folder, but attempts to call "/../" aren't working... How can I then load other resources which are not nested in my classes dir? (I can change my output dir, but I think it will be very ugly...)
为什么我的资源的默认目录是输出文件夹?
如前所述,我想从另一个文件夹中获取资源,但尝试调用“/../”不起作用......然后我如何加载未嵌套在我的类目录中的其他资源?(我可以更改我的输出目录,但我认为它会非常难看...)
采纳答案by angel_navarro
You must put them in the root of "src/" folder ;-)
您必须将它们放在“src/”文件夹的根目录中;-)
SRC/ folder is compiled to BUILD/CLASSES/, so all you put in src/* goes to classes/*
src/ 文件夹被编译为 BUILD/CLASSES/,所以你在 src/* 中放入的所有内容都会转到 classes/*