java 如何创建一个 zip 文件并下载它？
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How to create a zip file and download it?
提问by Sagar
I am creating a zip file and downloading it. I am able to download all file files with out any error. But the files in the zip are placing in nested folders according to the files real path like C>Users>workspace>.metadata>.plugins>org.eclipse.wst.server.core>tmp0>wtpwebapps>finaldebrief while I am trying to zip 'finaldebrief' folder only. I want to get 'finaldebrief' folder directly in zip file. can someone help me out. Thanks in Advance.
我正在创建一个 zip 文件并下载它。我能够下载所有文件而没有任何错误。但是 zip 中的文件根据文件真实路径放置在嵌套文件夹中，例如 C>Users>workspace>.metadata>.plugins>org.eclipse.wst.server.core>tmp0>wtpwebapps>finaldebrief 而我正在尝试仅 zip 'finaldebrief' 文件夹。我想直接在 zip 文件中获取“finaldebrief”文件夹。有人可以帮我吗。提前致谢。
Here is my code
这是我的代码
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
int workshopid = Integer.parseInt(request.getParameter("currentworkshopid"));
javax.servlet.ServletContext context = getServletConfig().getServletContext();
String path = context.getRealPath("finaldebrief");
try
{
response.setContentType("application/zip");
response.setHeader("Content-Disposition", "attachment;filename=finaldebrief.zip");
ZipOutputStream zos = new
ZipOutputStream(response.getOutputStream());
zipDir(path + "/", zos);
zos.close();
}
catch(Exception e)
{
e.printStackTrace();
}
}
public void zipDir(String dir2zip, ZipOutputStream zos)
{
try
{
//create a new File object based on the directory we have to zip File
File zipDir = new File(dir2zip);
//get a listing of the directory content
String[] dirList = zipDir.list();
byte[] readBuffer = new byte[2156];
int bytesIn = 0;
//loop through dirList, and zip the files
for(int i=0; i<dirList.length; i++)
{
File f = new File(zipDir, dirList[i]);
if(f.isDirectory())
{
//if the File object is a directory, call this
//function again to add its content recursively
String filePath = f.getPath();
// String filePath = f.getCanonicalPath();
zipDir(filePath, zos);
//loop again
continue;
}
//if we reached here, the File object f was not a directory
//create a FileInputStream on top of f
FileInputStream fis = new FileInputStream(f);
// create a new zip entry
ZipEntry anEntry = new ZipEntry(f.getPath());
//place the zip entry in the ZipOutputStream object
zos.putNextEntry(anEntry);
//now write the content of the file to the ZipOutputStream
while((bytesIn = fis.read(readBuffer)) != -1)
{
zos.write(readBuffer, 0, bytesIn);
}
//close the Stream
fis.close();
}
}
catch(Exception e)
{
e.printStackTrace();
}
}
回答by Howard
Within the line
线内
ZipEntry anEntry = new ZipEntry(f.getPath());
you specify the path inside your zip file (i.e. f.getPath()). If you want a shorter path or none at all just manipulate this part (e.g. f.getName()).
您在 zip 文件中指定路径（即f.getPath()）。如果您想要更短的路径或根本没有路径，只需操纵这部分（例如f.getName()）。
