php 如何通过对合并值求和来合并两个数组
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How to merge two arrays by summing the merged values
提问by Erick
Possible Duplicate:
PHP: How to sum values of the array of the same key
可能的重复：
PHP：如何对相同键的数组的值求和
I am looking for an array_merge()function that does NOT replace values, but ADDS them.
我正在寻找一个array_merge()不替换值但添加它们的函数。
Example, this is the code I am trying:
例如，这是我正在尝试的代码：
echo "<pre>";
$a1 = array(
"a" => 2
,"b" => 0
,"c" => 5
);
$a2 = array(
"a" => 3
,"b" => 9
,"c" => 7
,"d" => 10
);
$a3 = array_merge($a1, $a2);
print_r($a3);
Sadly, this outputs this:
可悲的是，这会输出：
Array
(
[a] => 3
[b] => 9
[c] => 7
[d] => 10
)
I then tried, instead of array_merge, just simply adding the two arrays
然后我尝试，而不是array_merge，只是简单地添加两个数组
$a3 = $a1 + $a2;
But this outputs
但这输出
Array
(
[a] => 2
[b] => 0
[c] => 5
[d] => 10
)
What I truly want is to be able to pass as many arrays as needed, and then get their sum. So in my example, I want the output to be:
我真正想要的是能够根据需要传递尽可能多的数组，然后得到它们的总和。所以在我的例子中，我希望输出是：
Array
(
[a] => 5
[b] => 9
[c] => 12
[d] => 10
)
Of course I can schlepp and build some function with many foreachetc, but am looking or a smarter, cleaner solution. Thanks for any pointers!
当然，我可以 schlepp 并使用许多foreach等构建一些功能，但我正在寻找或更智能，更清洁的解决方案。感谢您的任何指点！
回答by deceze
$sums = array();
foreach (array_keys($a1 + $a2) as $key) {
$sums[$key] = (isset($a1[$key]) ? $a1[$key] : 0) + (isset($a2[$key]) ? $a2[$key] : 0);
}
You couldshorten this to the following using the error suppression operator, but it should be considered ugly:
您可以使用错误抑制运算符将其缩短为以下内容，但它应该被认为是丑陋的：
$sums = array();
foreach (array_keys($a1 + $a2) as $key) {
$sums[$key] = @($a1[$key] + $a2[$key]);
}
Alternatively, some mapping:
或者，一些映射：
$keys = array_fill_keys(array_keys($a1 + $a2), 0);
$sums = array_map(function ($a1, $a2) { return $a1 + $a2; }, array_merge($keys, $a1), array_merge($keys, $a2));
Or sort of a combination of both solutions:
或者两种解决方案的组合：
$sums = array_fill_keys(array_keys($a1 + $a2), 0);
array_walk($sums, function (&$value, $key, $arrs) { $value = @($arrs[0][$key] + $arrs[1][$key]); }, array($a1, $a2));
I think these are concise enough to adapt one of them on the spot whenever needed, but to put it in terms of a function that accepts an unlimited number of arrays and sums them:
我认为这些足够简洁，可以在需要时在现场调整其中一个，但把它放在一个接受无限数量数组并对它们求和的函数方面：
function array_sum_identical_keys() {
$arrays = func_get_args();
$keys = array_keys(array_reduce($arrays, function ($keys, $arr) { return $keys + $arr; }, array()));
$sums = array();
foreach ($keys as $key) {
$sums[$key] = array_reduce($arrays, function ($sum, $arr) use ($key) { return $sum + @$arr[$key]; });
}
return $sums;
}
回答by Wesley Murch
My contribution:
我的贡献：
function array_merge_numeric_values()
{
$arrays = func_get_args();
$merged = array();
foreach ($arrays as $array)
{
foreach ($array as $key => $value)
{
if ( ! is_numeric($value))
{
continue;
}
if ( ! isset($merged[$key]))
{
$merged[$key] = $value;
}
else
{
$merged[$key] += $value;
}
}
}
return $merged;
}
Pass as many arrays to it as you want. Feel free to add some more defense, ability to accept multidimensional arrays, or type checking.
根据需要将尽可能多的数组传递给它。随意添加更多防御、接受多维数组的能力或类型检查。
回答by Haim Evgi
its not so complicate do something like:
它并不那么复杂，请执行以下操作：
$a3 = $a1;
foreach($a2 as $k => $v) {
if(array_key_exists($k, $a3)) {
$a3[$k] += $v;
} else {
$a3[$k] = $v;
}
}
回答by Sanjeev Kumar Jha
You can use array_push function.I hope it will help you
你可以使用 array_push 函数，希望对你有帮助
foreach($a2 as $a2){
array_push($a1, $a2);
}
print_r($a1);
Output:
Array
(
[a] => 2
[b] => 0
[c] => 5
[0] => 3
[1] => 9
[2] => 7
[3] => 10
)
OR you can change your logic in key value with numbers.It works even it have same number as follows:
或者您可以使用数字更改键值中的逻辑。即使它具有相同的数字，它也可以工作，如下所示：
<?php
$beginning = array(1 => 'foo');
$end = array(1 => 'bar');
$result = array_merge((array)$beginning, (array)$end);
print_r($result);
?>
Output:
Array (
[0] => foo
[1] => bar
)
Enjoy!!!!!!!!!!!!!!
享受！！！！！！！！！！！！！！
