告诉 AppleScript 构建 XCode 项目
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Tell AppleScript To Build XCode Project
提问by chuan
The following are the steps I would like to have:
以下是我想要的步骤：
- launch xcode
- open a specific xcodeproj file
- build and debug it
- quit xcode
- 启动 xcode
- 打开一个特定的 xcodeproj 文件
- 构建和调试它
- 退出 xcode
The following is my first attempt to write AppleScript:
以下是我第一次尝试编写 AppleScript：
tell application "Xcode"
tell project "iphone_manual_client"
debug
end tell
close project "iphone_manual_client"
end tell
This only works when xcode has this project opened. I would like to have the project to be opened only when it is necessary to do so.
这仅在 xcode 打开此项目时有效。我希望只有在必要时才打开该项目。
Can any AppleScript gurus out there points me to the right direction? Thanks.
任何 AppleScript 专家都可以指出我正确的方向吗？谢谢。
-chuan-
-传-
采纳答案by chuan
I think I managed to solve it. The following is the AppleScript:
我想我设法解决了它。以下是 AppleScript：
tell application "Xcode"
open "Users:chuan:Desktop:iphone_manual_client:iphone_manual_client.xcodeproj"
tell project "iphone_manual_client"
clean
build
(* for some reasons, debug will hang even the debug process has completed.
The try block is created to suppress the AppleEvent timeout error
*)
try
debug
end try
end tell
quit
end tell
The path has to be in format of ":" instead of "/". The only problem now is that after the debug console has done its job, AppleScript seems to "hang" as though waiting for something to happen. I need to do more research on AppleScript to know what is wrong with the script.
路径的格式必须是“:”而不是“/”。现在唯一的问题是，在调试控制台完成其工作后，AppleScript 似乎“挂起”，好像在等待某事发生。我需要对 AppleScript 进行更多研究以了解脚本有什么问题。
回答by stefanB
I'm not sure about AppleScript but you can compile it from command line, without opening xcode ide, like this:
我不确定 AppleScript，但您可以从命令行编译它，而无需打开 xcode ide，如下所示：
xcodebuild -configuration Debug -target WhatATool -project WhatATool.xcodeproj
Where configuration is obvious option, target is the name in Target list of xcode and the project name at the end.
其中配置是明显的选项，target 是 xcode 的 Target 列表中的名称和最后的项目名称。
回答by cdespinosa
Since debugging can take an arbitrary amount of time, you probably want a "with timeout of seconds" / "end timeout" block around the debug message.
由于调试可能需要任意长的时间，因此您可能需要在调试消息周围使用“超时秒数”/“结束超时”块。
