MySQL 在触发器中获取最新插入的 ID？
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Get the latest inserted id in a trigger?
提问by ajsie
I use a trigger to insert a row and want to use the last created id for using in the subsequent query.
我使用触发器插入一行，并希望使用上次创建的 id 用于后续查询。
How could I do this?
我怎么能这样做？
The code looks like:
代码如下：
BEGIN
IF (NEW.counter >= 100) THEN
INSERT INTO tagCategories (name, counter) VALUES ('unnamed', NEW.counter);
// here i want to have access to the above inserted id
UPDATE tagCategories2tagPairs SET tagCategoryId = <<ID_HERE>> WHERE tagPairId = OLD.id
END IF;
END
回答by Mitch Wheat
Have you looked at LAST_INSERT_ID()? But be aware:
你看过LAST_INSERT_ID()吗？但请注意：
If you insert multiple rows using a single INSERT statement, LAST_INSERT_ID() returns the value generated for the first inserted row only.
如果使用单个 INSERT 语句插入多行，则 LAST_INSERT_ID() 仅返回为第一个插入的行生成的值。
回答by AtlantaKid
I wanted to use a company initials like "AAA" and add the insert ID to it and use it as a internal company ID and this is how I picked up the last current insert ID
我想使用像“AAA”这样的公司首字母缩写并将插入 ID 添加到其中并将其用作内部公司 ID，这就是我获取最后一个当前插入 ID 的方式
DELIMITER //
CREATE TRIGGER company_run_before_insert BEFORE INSERT ON ap_company
FOR EACH ROW
BEGIN
SET @lastID = (SELECT id FROM ap_company ORDER BY id DESC LIMIT 1);
IF @lastID IS NULL OR @lastID = '' THEN
SET @lastID = 0;
END IF;
SET @lastID = @lastID +1;
SET NEW.ap_company_id = concat(NEW.company_initials,'-', @lastID);
END;
回答by Darkhan ZD
USE NEW.id
使用新的.id
BEGIN
insert INTO test_questions (test_id, question, variant1, variant2, variant3, w1, type_id)
SELECT NEW.id, t1.question, t1.v1, t1.v2, t1.v3, t1.answer, 1
FROM new_minitest_questions t1
WHERE t1.mt_id = NEW.old_id;
END
回答by user3785966
Following trigger will get the last Auto Increment value from the Information Schema. I had written this trigger to generate a slug.
以下触发器将从信息架构中获取最后一个自动增量值。我写了这个触发器来生成一个slug。
For instances, if the column's name is "Name" and column has a value such as "Robin Shankar", the trigger would replace spaces with "-" and also append the Auto Increment Id to the end of the slug, hence making a unique slug.
例如，如果列的名称是“Name”并且列具有诸如“Robin Shankar”之类的值，则触发器将用“-”替换空格，并将自动增量 ID 附加到 slug 的末尾，从而形成唯一的蛞蝓。
robin_shankar_9071
robin_shankar_9071
DELIMITER //
CREATE TRIGGER insert_slug_sd
BEFORE INSERT ON `your_table_name`
FOR EACH ROW
BEGIN
DECLARE auto_increment_ INT(11);
SELECT
`auto_increment`
INTO
auto_increment_
FROM INFORMATION_SCHEMA.TABLES
WHERE
table_name = 'your_table_name';
SET NEW.`Slug` = CONCAT(LOWER(REPLACE(NEW.`Name`,' ','-')),'-',auto_increment_);
END; //
DELIMITER;
回答by Антон Баранов
SET NEW.num=CONCAT("А-", (
SELECT `auto_increment`
FROM INFORMATION_SCHEMA.TABLES
WHERE table_name = 'menu')
)
