给定用户输入整数的 C++ 打印空格或制表符
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C++ printing spaces or tabs given a user input integer
提问by Slider
I need to turn user input (a number) into an output of TAB spaces. Example I ask user:
我需要将用户输入（一个数字）转换为 TAB 空格的输出。我问用户的例子：
cout << "Enter amount of spaces you would like (integer)" << endl;
cin >> n;
the (n) i need to turn it into an output like:
(n) 我需要把它变成一个输出，如：
cout << n , endl;
and what prints on the screen would be the spaces ex input is 5 out put |_| <~~~there are five spaces there.
屏幕上打印的是空格 ex input is 5 out put | _| <~~~那里有五个空格。
Sorry If I can't be clear, probably this is the reason I haven't been able to find an answer looking through other people's questions.
抱歉，如果我不清楚，可能这就是我无法通过其他人的问题找到答案的原因。
any help will be greatly appreciated.
任何帮助将不胜感激。
回答by James Kanze
Just use std::string:
只需使用std::string：
std::cout << std::string( n, ' ' );
In many cases, however, depending on what comes next, is may be
simpler to just add nto the parameter to an std::setw.
然而，在许多情况下，根据接下来发生的情况，n将参数添加到std::setw.
回答by taocp
cout << "Enter amount of spaces you would like (integer)" << endl;
cin >> n;
//print n spaces
for (int i = 0; i < n; ++i)
{
cout << " " ;
}
cout <<endl;
回答by Joseph Mansfield
You just need a loop that iterates the number of times given by nand prints a space each time. This would do:
您只需要一个循环来迭代由给出的次数n并每次打印一个空格。这会做：
while (n--) {
std::cout << ' ';
}
回答by StahlRat
I just happened to look for something similar and came up with this:
我只是碰巧寻找类似的东西并想出了这个：
std::cout << std::setfill(' ') << std::setw(n) << ' ';
回答by killscreen
Appending single space to output file with stream variable.
使用流变量将单个空格附加到输出文件。
// declare output file stream varaible and open file
ofstream fout;
fout.open("flux_capacitor.txt");
fout << var << " ";
// declare output file stream varaible and open file
ofstream fout;
fout.open("flux_capacitor.txt");
fout << var << " ";
