PHP：implode() 传递的参数无效
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PHP: implode() Invalid arguments passed
提问by suntrop
I am using Codeigniter and its validation rules - a custom callback validation. Anyway, this seems not to be CI related I think.
我正在使用 Codeigniter 及其验证规则 - 自定义回调验证。无论如何，我认为这似乎与 CI 无关。
I've got this function to return a string …
我有这个函数来返回一个字符串......
function array_implode($a)
{
return implode(',', $a);
}
… but I always get a message implode(): Invalid arguments passed
...但我总是收到一条消息 implode(): Invalid arguments传递
But var_dump()shows me this:
但是var_dump()给我看这个：
array(2) {
[0]=> string(10) "First item"
[1]=> string(11) "Second item"
}
What is wrong?
怎么了？
回答by Elias Van Ootegem
Why? Why would you write a function, that calls a std function? Why not write implode(',', $array);instead of adding the overhead of a function call?
为什么？为什么要编写一个调用 std 函数的函数？为什么不写implode(',', $array);而不是增加函数调用的开销？
Also: What var_dumpputs out an array? is it a dump of $ainside the array_implodefunction? To be sure $ais always going to be an array, and you insiston keeping your array_implodefunction, edit the code to look like this:
另外：什么var_dump放出一个数组？它是函数$a内部的转储array_implode吗？为了确保$a始终是一个数组，并且您坚持保留您的array_implode函数，请编辑代码如下所示：
function array_implode(array $a)
{//type hinting: this function will only work if $a is an array
return implode(',',$a);
}
回答by Jan Turoň
The code shouldn't throw any error. Probably there is something hidden. Use this function to find out the bug:
代码不应该抛出任何错误。恐怕有什么隐情。使用此函数找出错误：
function array_implode($a)
{
// print detailed info if $a is not array
if(!is_array($a)) {
var_dump($a); // what is in $a
var_dump(debug_backtrace()); // where exactly was it called?
exit;
}
return implode(',', $a);
}
回答by Baba
You can convert $ato array to make sure you are always working with arrays when using implode
您可以转换$a为数组以确保在使用时始终使用数组implode
function array_implode($a) {
return implode(',', (array) $a);
}
