php 使用 mktime 显示 2012 年的月份列表
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/10829424/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Displaying the list of months using mktime for the year 2012
提问by Sboniso Marcus Nzimande
Am am current facing a problem that need a solution ASAP.
我目前面临一个需要尽快解决的问题。
I am trying to list all months of the current year(2012) by using the following code:
我正在尝试使用以下代码列出当前年份(2012)的所有月份:
for ($m=1; $m<=12; $m++) {
$month = date('F', mktime(0,0,0,$m));
echo $month. '<br>';
}
But am getting the following unexpected output:
但我得到以下意外输出:
January March March May May July July August October October December December
一月三月三月五月七月七月八月十月十月十二月
What am I doing wrong please help!!!
我做错了什么请帮忙!!!
回答by iWizard
Try this:
尝试这个:
for ($m=1; $m<=12; $m++) {
$month = date('F', mktime(0,0,0,$m, 1, date('Y')));
echo $month. '<br>';
}
回答by Raab
Months are same for every year
每年的月份都一样
$array = array("January", "February",.....);
for ($m=0; $m<12; $m++) {
echo $array[$m]. '<br>';
}
回答by sephoy08
I guess you should loop it in this manner.
我想你应该以这种方式循环它。
for($i = 1 ; $i <= 12; $i++)
{
echo date("F",strtotime(date("Y")."-".$i."-01"));
echo "<br/>";
}
Or in your case, you want to use mktime()
或者在您的情况下,您想使用 mktime()
for($i = 1 ; $i <= 12; $i++)
{
echo date("F",mktime(0,0,0,$i,1,date("Y")));
echo "<br/>";
}
回答by Jan Turoň
Set dayin mktime()to 1, otherwise conversion is performed: 30.2.2012 = 1.3.2012
坐落day在mktime()到1,否则执行转换:30.2.2012 = 1.3.2012
$month = date('F', mktime(0,0,0,$m,1));
回答by omabra
Pay attention to the localization.
注意本地化。
You can also use this
你也可以用这个
setlocale(LC_TIME, 'it_IT');
for($m=1;$m<=12;$m++){
echo strftime("%B", mktime(0, 0, 0, $m, 12));
}
Changing the parameter on the function setlocale() you can display the localized text.
更改函数 setlocale() 上的参数可以显示本地化文本。

