Python 如何在 jinja2/flask 中获取当前 URL（request.url 不起作用）
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How to get current URL in jinja2/flask (request.url not working)
提问by alias51
Is there a way to print the current URL in Jinja2/Flask?
有没有办法在 Jinja2/Flask 中打印当前 URL？
E.g. if the current URL is http://www.domain.com/example/1/2
例如，如果当前 URL 是 http://www.domain.com/example/1/2
{{ request.path }}works and prints /example/1/2, but how to I get the full URL with http:// as well?
{{ request.path }}工作和打印/example/1/2，但如何使用 http:// 获取完整 URL？
From the docs (here){{ request.url }}should work, but it doesn't yield anything.
从文档（这里）{{ request.url }}应该可以工作，但它不会产生任何结果。
Thanks
谢谢
UPDATE
更新
Here are the render/context args from views.py:
以下是来自 views.py 的渲染/上下文参数：
class EventDetailView(EventObjectMixin, FormView):
template_name = 'gig/public/about.html'
context_object_name = 'event'
form_class = EventPurchaseTicketForm
def get_context_data(self, **kwargs):
context = super(EventDetailView, self).get_context_data(**kwargs)
...
return context
采纳答案by hugoxia
You can use {{ url_for(request.endpoint) }}, it works.
你可以使用{{ url_for(request.endpoint) }}，它的工作原理。
回答by gcerar
Find where you have similar code to this, usually found in controller.pyor __ init__.pyor views.py:
找到与此类似的代码，通常在controller.py或__ init__.py或views.py 中找到：
from flask import render_template
...
@app.route('/example/<arg1>/<arg2>')
def some_view_function(arg1, arg2):
...
return render_template('path/to/your/template.html')
With render_template()are request and other variables available to you.
您可以使用render_template()请求和其他变量。
回答by Dull Bananas
The flask.requestobject provides different ways to get the URL. See the documentationfor info.
该flask.request对象提供了获取 URL 的不同方法。有关信息，请参阅文档。
