java 不兼容的类型 - found:int required:boolean
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Incompatible Types - found:int required:boolean
提问by JcDav
I'm trying to display: EQUIVALENT if the first numerical input is equal to the second input. What's wrong with my code?
我试图显示：如果第一个数字输入等于第二个输入，则为 EQUIVALENT。我的代码有什么问题？
import java.io.*;
public class TwoNum{
public static void main(String[] args){
int number;
int number2;
String input1="";
String input2="";
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
System.out.println("Input a number: ");
try{
input1=in.readLine();
}catch(IOException e){
System.out.println("Error!");
}
number = Integer.parseInt(input1);
try{
input2=in.readLine();
}catch(IOException e){
System.out.println("Error!");
}
number2 = Integer.parseInt(input2);
if(number=number2)
{
System.out.println("EQUIVALENT");
}
if(number>number2)
{
System.out.println("GREATER THAN");
}
}
}
回答by Mark Peters
Use
利用
if(number==number2)
Instead of
代替
if(number=number2)
The first compares number2to numberand if they are equal evaluates to true. The second assignsthe value of number2to the variable numberand the expression evaluates to number/number2, an int.
第一个比较number2，以number和它们是否相等的计算结果为true。第二个将的值分配给number2变量number，表达式的计算结果为 number/number2，一个 int。
Link
关联
回答by Ray Toal
The expression number=number2is an assignment expression producing an integer. But a boolean is expected in this context. You want ==instead of =. Common mistake.
该表达式number=number2是一个产生整数的赋值表达式。但是在这种情况下需要一个布尔值。你想要==而不是=. 常见的错误。
回答by Harry Joy
Your first condition should be:
你的第一个条件应该是：
if(number==number2)
In if condition use ==to compare 2 integers. Also don't use if in both condition use else if(). Using ifin both will check condition for both even though first condition is true it will check for second condition and you are missing 3rd condition for LESS THAN.
在 if 条件中用于==比较 2 个整数。也不要使用 if 在两种情况下都使用else if(). if在两者中使用将检查两者的条件，即使第一个条件为真，它也会检查第二个条件，而您缺少LESS THAN.
