如何在 Python 中使用空分隔符拆分字符串
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How to split a string using an empty separator in Python
提问by Saullo G. P. Castro
What is a good way to do some_string.split('')in python? This syntax gives an error:
some_string.split('')在 python 中做什么的好方法是什么？此语法给出了错误：
a = '1111'
a.split('')
ValueError: empty separator
I would like to obtain:
我想获得：
['1', '1', '1', '1']
采纳答案by TerryA
Use list():
使用list()：
>>> list('1111')
['1', '1', '1', '1']
Alternatively, you can use map()(Python 2.7 only):
或者，您可以使用map()（仅限 Python 2.7）：
>>> map(None, '1111')
['1', '1', '1', '1']
Time differences:
时差：
$ python -m timeit "list('1111')"
1000000 loops, best of 3: 0.483 usec per loop
$ python -m timeit "map(None, '1111')"
1000000 loops, best of 3: 0.431 usec per loop
回答by oleg
One can cast strings to list directly
可以直接将字符串转换为列表
>>> list('1111')
['1', '1', '1', '1']
or using list comprehensions
或使用列表理解
>>> [i for i in '1111']
['1', '1', '1', '1']
second way can be useful if one wants to split strings for substrings more than 1 symbol length
如果想要为超过 1 个符号长度的子字符串拆分字符串，则第二种方法可能很有用
>>> some_string = '12345'
>>> [some_string[i:i+2] for i in range(0, len(some_string), 2)]
['12', '34', '5']
回答by Lennart Regebro
Strings are iterables and can be indexed, hence you don't really need to split it at all:
字符串是可迭代的并且可以被索引，因此你根本不需要拆分它：
>>> for char in '11111':
... print char
...
1
1
1
1
1
>>> '11111'[4]
'1'
You can "split" it with a call to list, but it doesn't make much difference:
您可以通过调用 list 来“拆分”它，但这并没有太大区别：
>>> for char in list('11111'):
... print char
...
1
1
1
1
1
>>> list('11111')[4]
'1'
So you only need to do this if your code explicitly expects a list. For example:
因此，只有当您的代码明确需要一个列表时，您才需要这样做。例如：
>>> list('11111').append('2')
>>> l = list('11111')
>>> l.append(2)
>>> l
['1', '1', '1', '1', '1', 2]
This doesn't work with a straight string:
这不适用于直字符串：
>>> l.append('2')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
AttributeError: 'str' object has no attribute 'append'
In that case you would need:
在这种情况下，您将需要：
>>> l += '2'
>>> l
'111112'
回答by Amalraj Victory
Method #1:
方法#1：
s="Amalraj"
l=[i for i in s]
print(l)
Output:
输出：
['A', 'm', 'a', 'l', 'r', 'a', 'j']
Method #2:
方法#2：
s="Amalraj"
l=list(s)
print(l)
Output:
输出：
['A', 'm', 'a', 'l', 'r', 'a', 'j']
Method #3:
方法#3：
import re; # importing regular expression module
s="Amalraj"
l=re.findall('.',s)
print(l)
Output:
输出：
['A', 'm', 'a', 'l', 'r', 'a', 'j']
