javascript 为什么JSFiddle不输出这段代码的结果

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时间:2020-10-27 15:31:23  来源:igfitidea点击:

Why doesn't JSFiddle output results for this code

javascriptjsfiddle

提问by Trevor

I have been using the Firebug javascript console to test short scripts. Several people have suggested using JSFiddle instead. The problem is I can't seem to figure out how to do this. I enter my code in the js panel and hit run but nothing happens. I am assuming something should output to results? I tried different settings, reading the JSFiddle documentation, reading other questions posted on Stackoverflow, but I can't figure it out. It seems like it should be so simple. Maybe it only works if I call it from HTML? http://jsfiddle.net/nngrey/QgxCn/(I had to include my code to reference the link to JSFiddle.)

我一直在使用 Firebug javascript 控制台来测试短脚本。有几个人建议改用 JSFiddle。问题是我似乎无法弄清楚如何做到这一点。我在 js 面板中输入我的代码并点击运行但没有任何反应。我假设某些东西应该输出到结果?我尝试了不同的设置,阅读 JSFiddle 文档,阅读 Stackoverflow 上发布的其他问题,但我无法弄清楚。好像应该这么简单。也许只有当我从 HTML 调用它时才有效?http://jsfiddle.net/nngrey/QgxCn/(我必须包含我的代码以引用指向 JSFiddle 的链接。)

function Palindrome(str) {
    str = str.split("");
    for (var i = 0; i < str.length; i++) {
        if (str[i] === " ") {
            str.splice(i, 1);
        }
    }
    revStr = str.reverse().join("");
    str = str.join("");
    if (revStr === str) {
        return true;
    } else {
        return false;
    }
    return str;
}

str = "dont nod";
Palindrome(str);

回答by redOctober13

You can use this jsFiddle to output stuff with console.log. Same idea as alert(), but without a popup you have to close. Thanks to Wayne Koort.

你可以使用这个 jsFiddle 来输出带有 console.log 的东西。与 alert() 的想法相同,但没有弹出窗口,您必须关闭。感谢韦恩库尔特

http://jsfiddle.net/TEHLb/

http://jsfiddle.net/TEHLb/

var consoleLine = "<p class=\"console-line\"></p>";
console = {
    log: function (text) {
        $("#console-log").append($(consoleLine).html(text));
    }
};
var myVar = "foo";
console.log('Your variable has the value ' + myVar);

回答by Trevor

Without any html to display your answer you can alert it to see the results.

没有任何 html 来显示您的答案,您可以提醒它查看结果。

function Palindrome(str) {
  str = str.split("");
  for (var i = 0; i < str.length; i++) {
    if (str[i] === " ") {
        str.splice(i, 1);
    }
}
revStr = str.reverse().join("");
str = str.join("");
if (revStr === str) {
    return true;
} else {
    return false;
}
    return str;
}

str = "dont nod";
alert(Palindrome(str));

回答by iJade

you need alert(Palindrome(str));

你需要 alert(Palindrome(str));

try this demo

试试这个演示