php 从数组中删除前 2 个
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Remove first 2 from Array
提问by karim79
I have this simple array and I'd like to know how I can stop the first 2segments from showing.
我有这个简单的数组，我想知道如何阻止前 2 个片段的显示。
if(preg_match_all('/<td[^>]*class="sourceNameCell">(.*?)<\/td>/si', $printable, $matches, PREG_SET_ORDER));{
foreach($matches as $match) {
$data = "$match[1]";
$array = array();
preg_match( '/src="([^"]*)"/i', $data, $array ) ;
print_r("$array[1]") ;
}
Any help would be great, Thanks!
任何帮助都会很棒，谢谢！
采纳答案by Moshe Eshel
Stop from showing or removing?
停止显示或删除？
for removing:
用于去除：
$array = array();
preg_match( '/src="([^"]*)"/i', $data, $array ) ;
// The following lines will remove values from the first two indexes.
unset($array[0]);
unset($array[1]);
// This line will re-set the indexes (the above just nullifies the values...) and make a new array without the original first two slots.
$array = array_values($array);
// The following line will show the new content of the array
var_dump($array);
Hope this helps!
希望这可以帮助！
回答by karim79
回答by jishi
Use array_slice($array, 2, count($array))or make your regexp skip the first two if possible.
array_slice($array, 2, count($array))如果可能，使用或让您的正则表达式跳过前两个。
You could also invoke array_shift() twice on the array. This might be more optimal since it shouldn't need to make a copy of the array.
您还可以在数组上调用 array_shift() 两次。这可能更优化，因为它不需要复制数组。
