PHP 循环 1 到 10
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/40716464/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
PHP Loop 1 to 10
提问by Jelles
I need to make a loop in php that does 1 + 2 + 3 + 4 .... + 10 = 55 but icant get it to work. I did this:
我需要在 php 中创建一个循环，执行 1 + 2 + 3 + 4 .... + 10 = 55 但不能让它工作。我这样做了：
<!DOCTYPE html>
<html>
<head>
<title></title>
</head>
<body>
<?php
for ($i = 1; $i <= 10; $i++){
$sul = $i + $i + $i + $i + $i + $i + $i + $i + $i + $i;
echo "$i + $i + $i + $i + $i + $i + $i + $i + $i + $i = $sul<br>";
};
?>
</body>
Hope you can help me thanks :)
希望你能帮助我谢谢:)
回答by Karol Gasienica
This code should help you:
此代码应该可以帮助您：
<?php
$sum = 0;
for($i = 1; $i<=10; $i++) {
$sum = $sum + $i;
}
echo $sum;
?>
You are incorrect using loop.
您使用循环不正确。
Explanation
解释
I think it will be easier to understand with following table:
我认为使用下表会更容易理解：
_____________________
|JUMP | $i | $sum |
|1 | 1 | 1 |
|2 | 2 | 3 |
|3 | 3 | 6 |
|4 | 4 | 10 |
|5 | 5 | 15 |
|6 | 6 | 21 |
|7 | 7 | 28 |
|8 | 8 | 36 |
|9 | 9 | 45 |
|10 | 10 | 55 |
More about foryou can read in PHP: for
Update
更新
If you want your structure it can be as follows:
如果你想要你的结构，它可以如下：
<?php
$sum = 0;
$str = '';
for($i = 1; $i<=10; $i++) {
$sum = $sum + $i;
$str .= $i == 10 ? $i." = " : $i." + ";
}
echo $str.$sum;
?>
And it will output 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55
它会输出 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55
回答by Jonnix
Something like this perhaps?
也许是这样的？
$range = range(1, 10);
$sum = array_sum($range);
echo implode(' + ', $range) . ' = ' . $sum;
range() - http://php.net/range
范围（） - http://php.net/range
array_sum() - http://php.net/array_sum
array_sum() - http://php.net/array_sum
implode() - http://php.net/implode
implode() - http://php.net/implode
回答by Murad Hasan
Just make a for loop from starting 1 to 10, like given below. You need to initialize the counter as 0 and while the loop executes you need to collect / sum them to the counter and finally outside the loop print/ echo the counter.
只需从开始 1 到 10 进行 for 循环，如下所示。您需要将计数器初始化为 0，并且在循环执行时您需要将它们收集/求和到计数器，最后在循环之外打印/回显计数器。
$count = 0;
$string = '';
for ($i = 1; $i <= 10; $i++){
$count += $i;
$string .= ($i == 10) ? $i : $i." + ";
}
echo $string." = ".$count; // 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55
This is a very simple and straight forward way, you can do this using some array functions which is built-in in PHP.
这是一种非常简单直接的方法，您可以使用 PHP 内置的一些数组函数来完成此操作。
回答by Ronald
If you don't want to hardcode it, you can do this
如果你不想硬编码它，你可以这样做
<?php
$answer = 0;
for ($i = 1; $i <= 10; $i++){
$answer = $i + $answer;
if ($i == 10) {
echo $i." = ".$answer;
}
else {
echo $i." + ";
}
};
?>
Output is:
输出是：
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55
回答by Mauricio Irace
A for loop actually repeats a block of code n times, you syntax is right buy your semantic is wrong: initializes a counter in 0 and add i to the counter in each step as the other people say. Also, if is not compulsory to use a for, remember that the sum of first n natural numbers is n(n+1)/2, so no loop is actually needed
for 循环实际上将代码块重复 n 次，您的语法是正确的，但您的语义是错误的：在 0 中初始化一个计数器并在每个步骤中将 i 添加到其他人所说的计数器中。另外，如果不是强制使用for，记住前n个自然数的和是n(n+1)/2，所以实际上不需要循环
回答by d3p4n5hu
There you go:
你去吧：
$sum = 0;
for($i = 1; $i <= 10; $i++){
if($i == 10){
echo $i;
} else {
echo $i." + ";
}
$sum = $sum + $i;
}
echo " = ".$sum;
回答by user2693928
<!DOCTYPE html>
<html>
<head>
<title></title>
</head>
<body>
<?php
$n = 10;
$items = range(1, $n);
$sum = array_sum($items);
echo implode('+', $items) . ' = ' . $sum;
?>
</body>
This way is shorter. You generate the array from 1 to $n(10);
这种方式更短。您生成从 1 到 $n(10) 的数组；
Then you calculate the sum of the items.
然后你计算项目的总和。
And then join each element with '+' and add the sum.
然后用“+”连接每个元素并添加总和。
