Git diff --name-only 并复制该列表
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Git diff --name-only and copy that list
提问by BazZy
I just want to get a list of changed files between two revisions, which is simple:
我只想获取两个修订版之间已更改文件的列表，这很简单：
git diff -–name-only commit1 commit2 > /path/to/my/file
But, what should I write, if I want copy all that listed files to another place? And I need completely identical directory structure for copied files.
但是，如果我想将所有列出的文件复制到另一个地方，我应该写什么？我需要完全相同的目录结构来复制文件。
For example, I have modified and added files:
例如，我修改并添加了文件：
/protected/texts/file1.txt
/protected/scripts/index.php
/public/pics/pic1.png
I want to have in /home/changes/all those changed and added files:
我想在/home/changes/所有这些更改和添加的文件中：
/home/changes/protected/texts/file1.txt
/home/changes/protected/scripts/index.php
/home/changes/public/pics/pic1.png
采纳答案by York
Try the following command, which I have tested:
尝试以下我已经测试过的命令：
$ cp -pv --parents $(git diff --name-only) DESTINATION-DIRECTORY
回答by Mark Longair
The following should work fine:
以下应该可以正常工作：
git diff -z --name-only commit1 commit2 | xargs -0 -IREPLACE rsync -aR REPLACE /home/changes/protected/
To explain further:
进一步解释：
The
-zto withgit diff --name-onlymeans to output the list of files separated with NUL bytes instead of newlines, just in case your filenames have unusual characters in them.The
-0toxargssays to interpret standard input as a NUL-separated list of parameters.The
-IREPLACEis needed since by defaultxargswould append the parameters to the end of thersynccommand. Instead, that says to put them where the laterREPLACEis. (That's a nice tip from this Server Fault answer.)The
-aparameter torsyncmeans to preserve permissions, ownership, etc. if possible. The-Rmeans to use the full relative path when creating the files in the destination.
在
-z与git diff --name-only同NUL分隔的文件的方式输出列表字节而不是换行，以防万一您的文件名中都有特殊字符。该
-0到xargs说，解释标准作为输入参数的NUL分隔的列表。的
-IREPLACE需要，因为默认xargs将参数追加到的结束rsync命令。相反，这意味着将它们放在后者所在的REPLACE位置。（这是这个 Server Fault answer的一个很好的提示。）在
-a对参数rsync的手段维护权限，所有权等如果可能的话。的-R手段来创建在目标文件时使用完整的相对路径。
Update:if you have an old version of xargs, you'll need to use the -ioption instead of -I. (The former is deprecated in later versions of findutils.)
更新：如果您有旧版本的xargs，则需要使用该-i选项而不是-I。（前者在更高版本的findutils. 中已弃用。）
回答by kolypto
Here's a one-liner:
这是一个单行：
List changed files & pack them as *.zip:
列出更改的文件并将它们打包为 *.zip：
git diff --name-only | zip patched.zip -@
List last committed changed files & pack them as *.zip:
列出最后提交的更改文件并将它们打包为 *.zip：
git diff --name-only HEAD~ HEAD | zip patched.zip -@
回答by Mark
zip update.zip $(git diff --name-only commit commit)
回答by Surjit Sidhu
#!/bin/bash
# Target directory
TARGET=/target/directory/here
for i in $(git diff --name-only)
do
# First create the target directory, if it doesn't exist.
mkdir -p "$TARGET/$(dirname $i)"
# Then copy over the file.
cp -rf "$i" "$TARGET/$i"
done
https://stackoverflow.com/users/79061/sebastian-paaske-t%c3%b8rholm
https://stackoverflow.com/users/79061/sebastian-paaske-t%c3%b8rholm
回答by knight2016
It works perfectly.
它完美地工作。
git diff 1526043 82a4f7d --name-only | xargs zip update.zip
git diff 1526043 82a4f7d --name-only |xargs -n 10 zip update.zip
回答by hexten
No-one has mentioned cpiowhich is easy to type, creates hard links and handles spaces in filenames:
没有人提到cpio哪个易于输入、创建硬链接并处理文件名中的空格：
git diff --name-only $from..$to | cpio -pld outdir
