在 Bash 中循环字母
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Looping through alphabets in Bash
提问by behzad.nouri
I want to mvall the files starting with 'x' to directory 'x'; something like:
我想把mv所有以“x”开头的文件放到目录“x”中；就像是：
mv path1/x*.ext path2/x
and do it for all alphabet letters a, ..., z
并对所有字母 a, ..., z 执行此操作
How can I write a bash script which makes 'x' loops through the alphabet?
如何编写一个 bash 脚本，使“x”在字母表中循环？
回答by Kamil Dziedzic
for x in {a..z}
do
echo "$x"
mkdir -p path2/${x}
mv path1/${x}*.ext path2/${x}
done
回答by Mat
This should get you started:
这应该让你开始：
for letter in {a..z} ; do
echo $letter
done
回答by Luis Mu?oz
here's how to generate the Spanish alphabet using nested brace expansion
这是使用嵌套括号扩展生成西班牙字母表的方法
for l in {{a..n},?,{o..z}}; do echo $l ; done | nl
1 a
...
14 n
15 ?
16 o
...
27 z
Or simply
或者干脆
echo -e {{a..n},?,{o..z}}"\n" | nl
If you want to generate the obsolete29 characters Spanish alphabet
如果要生成过时的29 个字符的西班牙字母表
echo -e {{a..c},ch,{d..l},ll,{m,n},?,{o..z}}"\n" | nl
Similar could be done for French alphabet or German alphabet.
对法语字母或德语字母也可以进行类似的操作。
回答by anishsane
回答by Thanh Trung
With uppercase as well
也有大写
for letter in {{a..z},{A..Z}}; do
echo $letter
done
回答by Alphons
This question and the answers helped me with my problem, partially.
I needed to loupe over a part of the alphabetin bash.
这个问题和答案部分地帮助了我解决我的问题。
我需要在 bash 中放大部分字母表。
Although the expansion is strictly textual
虽然扩展是严格的文本
I found a solution:and made it even more simple:
我找到了一个解决方案：并使它更简单：
START=A
STOP=D
for letter in $(eval echo {$START..$STOP}); do
echo $letter
done
Which results in:
结果是：
A
B
C
D
Hope its helpful for someone looking for the same problem i had to solve, and ends up here as well
希望它对寻找我必须解决的相同问题的人有所帮助，并且最终也在这里
