PHP：将日期转换为秒？
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PHP: convert date into seconds?
提问by Usman
I've a date like Tue Dec 15 2009. How can I convert it into seconds?
我有一个像Tue Dec 15 2009这样的约会。如何将其转换为秒？
Update: How can I convert a date formatted as above to Unix timestamp?
更新：如何将上述格式的日期转换为 Unix 时间戳？
回答by Pekka
I assume by seconds you mean a UNIX timestamp.
我假设秒是指UNIX 时间戳。
strtotime()should help.
strtotime()应该会有所帮助。
回答by Pascal MARTIN
You can use the strtotimefunction to convert that date to a timestamp :
您可以使用该strtotime函数将该日期转换为时间戳：
$str = 'Tue Dec 15 2009';
$timestamp = strtotime($str);
And, just to be sure, let's convert it back to a date as a string :
而且，为了确定，让我们将其转换回字符串形式的日期：
var_dump(date('Y-m-d', $timestamp));
Which gives us :
这给了我们：
string '2009-12-15' (length=10)
(Which proves strtotimedid understand our date ^^ )
（这证明strtotime确实了解我们的约会^^）
[edit 2012-05-19] as some other questions might point some readers here:Note that strtotime()is not the only solution, and that you should be able to work with the DateTimeclass, which provides some interesting features -- especially if you are using PHP >= 5.3
[edit 2012-05-19] 因为其他一些问题可能会指向这里的一些读者：请注意，这strtotime()不是唯一的解决方案，您应该能够使用DateTime该类，它提供了一些有趣的功能 - 特别是如果您正在使用PHP >= 5.3
In this case, you could use something like the following portion of code :
在这种情况下，您可以使用类似于以下代码部分的内容：
$str = 'Tue Dec 15 2009';
$format = 'D F d Y';
$dt = DateTime::createFromFormat($format, $str);
$timestamp = $dt->format('U');
DateTime::createFromFormat()allows one to create a DateTimeobject from almost any date, no matter how it's formated, as you can specify the format you date's in (This method is available with PHP >= 5.3).
DateTime::createFromFormat()允许DateTime从几乎任何日期创建对象，无论它的格式如何，因为您可以指定日期的格式（此方法适用于 PHP >= 5.3）。
And DateTime::format()will allow you to format that object to almost any kind of date format -- including an UNIX Timestamp, as requested here.
并且DateTime::format()允许您将该对象格式化为几乎任何类型的日期格式 - 包括UNIX Timestamp，如此处所要求。
回答by hanse
You mean like an UNIX-timestamp? Try:
你的意思是像一个 UNIX 时间戳？尝试：
echo strtotime('Tue Dec 15 2009');
