java 如何在 JavaFX 的 ObservableList<Tab> 中循环
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How to loop in ObservableList<Tab> for JavaFX
提问by user1285928
I am working in JavaFX and I have this ObservableList<Tab>. Can you tell me how I can loop and get the content of a content of the list? maybe something like this:
我在 JavaFX 工作，我有这个ObservableList<Tab>. 你能告诉我如何循环并获取列表内容的内容吗？也许是这样的：
ObservableList<Tab>
for (....){
tabPane.getTabs().add(i);
)
回答by inyourcorner
Java 8 supports .forEach()
Java 8 支持 .forEach()
ObservableList<Tab> tabs = ...
tabs.forEach((tab) -> {
System.out.println("Stuff with "+tab);
});
回答by blalasaadri
You can use a ListIterator<Tab>like this:
你可以使用ListIterator<Tab>这样的：
ObservableList<Tab> list = ...;
Tab currentTab;
for(ListIterator<Tab> iterator = list.listIterator(); iterator.hasNext(); currentTab = iterator.next()) {
// use currentTab here
}
or even an enhanced for loop:
甚至增强的 for 循环：
for(Tab currentTab : list) {
// use currentTab here
}
回答by André Stannek
Do you mean a for each loop in which you do something with every element that's in the list?
您的意思是在每个循环中对列表中的每个元素执行某些操作吗？
ObservableList<Tab> myList = ...;
for (Tab tabPane : myList){
// Do whatever you want to do with tabPane
}
回答by jan.zanda
ObservableList<Tab> obList;
for(Tab tab : obList) {
tab.doWhateverYouWant(); // "tab" is the reference to current Tab in this loop.
}
回答by JeffinWithYa
Most likely there will be a get method to expose the Tabs. For example:
很可能会有一个 get 方法来公开选项卡。例如：
ObservableList<Tab> list = ...;
for (Tab tab: list.get()) {
// do something
}
