Android Webview POST
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Android Webview POST
提问by Se?or Reginold Francis
I am trying to accomplish something quite simple, yet I have found no good documentation on this. I have a webView, and I need to load a page in it that requires POST data. Seems like a simple process, yet I cannot find a way to display the result in a webView.
我试图完成一些非常简单的事情，但我没有找到关于此的好的文档。我有一个 webView，我需要在其中加载一个需要 POST 数据的页面。看起来像一个简单的过程，但我找不到在 webView 中显示结果的方法。
The process should be simple:
过程应该很简单：
query(with POST data) -> webserver -> HTML response -> WebView.
查询（带有 POST 数据）-> 网络服务器-> HTML 响应-> WebView。
I can submit data using a DefaultHttpClient, but this cannot be displayed in a WebView.
我可以使用 DefaultHttpClient 提交数据，但这无法在 WebView 中显示。
Any suggestions?
有什么建议？
Much Thanks
非常感谢
Solution
解决方案
private static final String URL_STRING = "http://www.yoursite.com/postreceiver";
public void postData() throws IOException, ClientProtocolException {
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("foo", "12345"));
nameValuePairs.add(new BasicNameValuePair("bar", "23456"));
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(URL_STRING);
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
String data = new BasicResponseHandler().handleResponse(response);
mWebView.loadData(data, "text/html", "utf-8");
}
采纳答案by TJF
Try this:
尝试这个：
private static final String URL_STRING = "http://www.yoursite.com/postreceiver";
public void postData() throws IOException, ClientProtocolException {
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("foo", "12345"));
nameValuePairs.add(new BasicNameValuePair("bar", "23456"));
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(URL_STRING);
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
}
I would recommend doing this as part of an AsyncTask and updating the WebView afterwards
我建议将此作为 AsyncTask 的一部分并在之后更新 WebView
回答by tarkeshwar
Two ways to load post response in webview:
在 webview 中加载 post 响应的两种方法：
webview.loadData(): Like what you have posted in your solution. But "content loaded through this mechanism does not have the ability to load content from the network".webview.postUrl(): Use this if post response needs to load content from the network. (NOTE: only accessible from api-level 5, which means no android 1.6 or lower)
webview.loadData()：就像您在解决方案中发布的内容一样。但是“通过这种机制加载的内容不具备从网络加载内容的能力”。webview.postUrl()：如果发布响应需要从网络加载内容，请使用此选项。（注意：只能从 api-level 5 访问，这意味着没有 android 1.6 或更低版本）
String postData = "username=my_username&password=my_password";
webview.postUrl(url,EncodingUtils.getBytes(postData, "BASE64"));
(source: http://www.anddev.org/other-coding-problems-f5/webview-posturl-postdata-t14239.html)
（来源：http: //www.anddev.org/other-coding-problems-f5/webview-posturl-postdata-t14239.html）
回答by HenryChuang
I use webView.loadData() to do client post, and it will display content of url, my code :
我使用 webView.loadData() 进行客户端发布，它将显示 url 的内容，我的代码：
public static void webview_ClientPost(WebView webView, String url, Collection< Map.Entry<String, String>> postData){
StringBuilder sb = new StringBuilder();
sb.append("<html><head></head>");
sb.append("<body onload='form1.submit()'>");
sb.append(String.format("<form id='form1' action='%s' method='%s'>", url, "post"));
for (Map.Entry<String, String> item : postData) {
sb.append(String.format("<input name='%s' type='hidden' value='%s' />", item.getKey(), item.getValue()));
}
sb.append("</form></body></html>");
webView.loadData(sb.toString(), "text/html", "UTF-8");
}
use function webview_ClientPost() :
使用函数 webview_ClientPost() ：
Map<String, String> mapParams = new HashMap<String, String>();
mapParams.put("param1", "111");
mapParams.put("param2", "222");
Collection<Map.Entry<String, String>> postData = mapParams.entrySet();
webview_ClientPost(webView1, "http://www.yoursite.com/postreceiver", postData);
回答by LatinSuD
If you use a WebView from the start could it work?
如果您从一开始就使用 WebView，它可以工作吗？
A Webview with a html/js that does the POST, and naturally displays the result.
带有 html/js 的 Webview 执行 POST，并自然地显示结果。
