jQuery：检查禁用的属性并添加/删除它？

jQuery: Checking for disabled attribute and adding/removing it?

提问by Sven

I select all input elements of a form like this:

我像这样选择表单的所有输入元素：

var fields = $( form + " :input" ).not( "button" );

How do I check if any of these inputs has the disabledattribute set and remove it when present?

如何检查这些输入中的任何一个是否disabled设置了属性并在存在时将其删除？

Also, I need to add it after is has been removed (and serialize the fields in between), is there an elegant way for this? Something like togglebut for attributes?

另外，我需要在删除后添加它（并序列化中间的字段），有没有一种优雅的方法？类似于toggle但对于属性？

回答by Ruben Infante

Assuming you are using jQuery 1.6 or above, the suggested method is to use .prop().

假设您使用 jQuery 1.6 或更高版本，建议的方法是使用.prop()。

fields.prop("disabled", false);

fields.prop("disabled", false);

If you need to have logic around each one, you could do something to the extent of

如果您需要对每个人都有逻辑，您可以在以下范围内做一些事情

var fields = $( form + " :input" ).not( "button" );
fields.each(function(index, element) {
    var isDisabled = $(element).is(':disabled');
    if (isDisabled) {
        $(element).prop('disabled', false);
    } else {
        // Handle input is not disabled
    }
});

jsfiddle

提琴手

回答by glosrob

You can use the disabledselector

您可以使用disabled选择器

$('input:disabled').attr('disabled', '');

See here

看这里

http://jsfiddle.net/JngR9/

http://jsfiddle.net/JngR9/

回答by Zubarik

To Remove

去除

$('input:disabled').removeProp('disabled');

or

或者

$('input:disabled').prop('disabled', 'disabled');

To Add

加上

$('input:disabled').prop('disabled', 'disabled');

回答by bipen

use :disabled Selector` try this

使用:disabled Selector` 试试这个

$('input:disabled').remove();