Bash - 如何在 sed 命令输出中保留换行符？
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Bash - how to preserve newline in sed command output?
提问by Jared Aaron Loo
Assuming I have a file BookDB.txt which stores data in the following format :
假设我有一个 BookDB.txt 文件，它以以下格式存储数据：
Harry Potter - The Half Blood Prince:J.K Rowling:40.30:10:50
The little Red Riding Hood:Dan Lin:40.80:20:10
Harry Potter - The Phoniex:J.K Rowling:50.00:30:20
Harry Potter - The Deathly Hollow:Dan Lin:55.00:33:790
Little Prince:The Prince:15.00:188:9
Lord of The Ring:Johnny Dept:56.80:100:38
Three Little Pig:Andrew Lim:89.10:290:189
All About Linux:Ubuntu Team:76.00:44:144
Catch Me If You Can:Mary Ann:23.60:6:2
Python for dummies:Jared Loo:15.99:1:10
I am trying to replace the (:) delimiter with (, ) in my output. It succeeds, but removes the newline from the output. Here is my code :
我试图在我的输出中用 (, ) 替换 (:) 分隔符。它成功了，但从输出中删除了换行符。这是我的代码：
TITLE=Potter
OUTPUT=$(cat BookDB.txt | grep $TITLE)
OUTPUT1=$(sed 's/:/, /g' <<< $OUTPUT)
echo $OUTPUT1
I want my output to look like this :
我希望我的输出看起来像这样：
Harry Potter - The Half Blood Prince, J.K Rowling, 40.30, 10, 50
Harry Potter - The Phoniex, J.K Rowling. 50.00. 30. 20
Harry Potter - The Deathly Hollow, Dan Lin, 55.00, 33, 790
However, it looks like this :
但是，它看起来像这样：
Harry Potter - The Half Blood Prince, J.K Rowling, 40.30, 10, 50 Harry Potter - The Phoniex, J.K Rowling, 50.00, 30, 20 Harry Potter - The Deathly Holl
ow, Dan Lin, 55.00, 33, 790
If anyone could share how to preserve the line break in the output, I would be very grateful!
如果有人可以分享如何在输出中保留换行符，我将不胜感激！
回答by Aserre
回答by anubhava
You can avoid catand do all in sed:
您可以避免cat并在 sed 中完成所有操作：
sed -n '/Potter/s/:/, /gp' file
Harry Potter - The Half Blood Prince, J.K Rowling, 40.30, 10, 50
Harry Potter - The Phoniex, J.K Rowling, 50.00, 30, 20
Harry Potter - The Deathly Hollow, Dan Lin, 55.00, 33, 790
回答by konsolebox
Using awk. Matching would be specific to the titles and doesn't include the author's name.
使用awk. 匹配将特定于标题，不包括作者姓名。
awk -F: -v OFS=', ' ' ~ /Potter/ { = ; print }' file
Output:
输出：
Harry Potter - The Half Blood Prince, J.K Rowling, 40.30, 10, 50
Harry Potter - The Phoniex, J.K Rowling, 50.00, 30, 20
Harry Potter - The Deathly Hollow, Dan Lin, 55.00, 33, 790
This gives no output:
这没有输出：
awk -F: -v OFS=', ' ' ~ /Rowling/ { = ; print }' file
But this will:
但这将：
awk -F: -v OFS=', ' ' ~ /Rowling/ { = ; print }' file
Output:
输出：
Harry Potter - The Half Blood Prince, J.K Rowling, 40.30, 10, 50
Harry Potter - The Phoniex, J.K Rowling, 50.00, 30, 20
To match against both title and author you can have:
要匹配标题和作者，您可以：
awk -F: -v OFS=', ' ' ~ /Potter/ && ~ /Rowling/ { = ; print }' file
Or to match if any validates:
或者匹配是否有任何验证：
awk -F: -v OFS=', ' ' ~ /Potter/, ~ /Rowling/ { = ; print }' file
