Java 如何除以得到十进制值？
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How do I divide so I get a decimal value?
提问by
I want to know how to get remainder and quotient in single value in Java.
我想知道如何在 Java 中获得单值的余数和商数。
Example:
例子：
3/2 I should get value as 1.5.
3/2 我应该得到 1.5 的价值。
If I use the /operator I get only the quotient. If I user the %operator I get only the remainder. How do I get both at a time in the same variable?
如果我使用/运算符，我只会得到商。如果我使用%运营商，我只会得到剩余部分。如何在同一个变量中同时获得两者？
回答by vladr
In your example, Java is performing integerarithmetic, rounding off the result of the division.
在您的示例中，Java 正在执行整数算术，四舍五入除法结果。
Based on your question, you would like to perform floating-point arithmetic. To do so, at least one of your terms must be specified as (or converted to) floating-point:
根据您的问题，您想执行浮点运算。为此，必须至少将您的一项指定为（或转换为）浮点数：
Specifying floating point:
指定浮点数：
3.0/2
3.0/2.0
3/2.0
Converting to floating point:
转换为浮点数：
int a = 2;
int b = 3;
float q = ((float)a)/b;
or
或者
double q = ((double)a)/b;
(See Java Traps: doubleand Java Floating-Point Number Intricaciesfor discussions on floatand double)
（参见Java的陷阱：双和Java的浮点数余光中对讨论float和double）
回答by recursive
quotient = 3 / 2;
remainder = 3 % 2;
// now you have them both
回答by Neil Coffey
Don't worry about it. In your code, just do the separate / and % operations as you mention, even though it might seem like it's inefficient. Let the JIT compiler worryabout combining these operations to get both quotient and remainder in a single machine instruction (as far as I recall, it generally does).
别担心。在您的代码中，只需执行您提到的单独 / 和 % 操作，即使它看起来效率低下。让 JIT 编译器担心组合这些操作以在单个机器指令中获得商和余数（据我所知，它通常是这样）。
回答by Cladius Fernando
Check this out: http://download.oracle.com/javase/1,5.0/docs/api/java/math/BigDecimal.html#divideAndRemainder%28java.math.BigDecimal%29
看看这个：http: //download.oracle.com/javase/1,5.0/docs/api/java/math/BigDecimal.html#divideAndRemainder%28java.math.BigDecimal%29
You just need to wrap your intor longvariable in a BigDecimalobject, then invoke the divideAndRemaindermethod on it. The returned array will contain the quotient and the remainder (in that order).
您只需要将int或long变量包装在BigDecimal对象中，然后在其上调用divideAndRemainder方法。返回的数组将包含商和余数（按该顺序）。
回答by user3559041
If you initialize both the parameters as float, you will sure get actual divided value.
For example:
如果您将两个参数都初始化为float，您肯定会得到实际的除法值。例如：
float RoomWidth, TileWidth, NumTiles;
RoomWidth = 142;
TileWidth = 8;
NumTiles = RoomWidth/TileWidth;
Ans:17.75.
答：17.75。
回答by Matthew
int a = 3;
int b = 2;
float c = ((float)a)/b
回答by Hesam
@recursive's solusion (The accepted answer) is 100% right. I am just adding a sample code for your reference.
@recursive 的解决方案（接受的答案）是 100% 正确的。我只是添加一个示例代码供您参考。
My case is to display price with two decimal digits.This is part of back-end response: "price": 2300, "currencySymbol": "CD", ....
我的情况是用两位小数显示价格。这是后端响应的一部分："price": 2300, "currencySymbol": "CD", ...。
This is my helper class:
这是我的助手类：
public class CurrencyUtils
{
private static final String[] suffix = { "", "K", "M" };
public static String getCompactStringForDisplay(final int amount)
{
int suffixIndex;
if (amount >= 1_000_000) {
suffixIndex = 2;
} else if (amount >= 1_000) {
suffixIndex = 1;
} else {
suffixIndex = 0;
}
int quotient;
int remainder;
if (amount >= 1_000_000) {
quotient = amount / 1_000_000;
remainder = amount % 1_000_000;
} else if (amount >= 1_000) {
quotient = amount / 1_000;
remainder = amount % 1_000;
} else {
return String.valueOf(amount);
}
if (remainder == 0) {
return String.valueOf(quotient) + suffix[suffixIndex];
}
// Keep two most significant digits
if (remainder >= 10_000) {
remainder /= 10_000;
} else if (remainder >= 1_000) {
remainder /= 1_000;
} else if (remainder >= 100) {
remainder /= 10;
}
return String.valueOf(quotient) + '.' + String.valueOf(remainder) + suffix[suffixIndex];
}
}
This is my test class (based on Junit 4):
这是我的测试类（基于 Junit 4）：
public class CurrencyUtilsTest {
@Test
public void getCompactStringForDisplay() throws Exception {
int[] numbers = {0, 5, 999, 1_000, 5_821, 10_500, 101_800, 2_000_000, 7_800_000, 92_150_000, 123_200_000, 9_999_999};
String[] expected = {"0", "5", "999", "1K", "5.82K", "10.50K", "101.80K", "2M", "7.80M", "92.15M", "123.20M", "9.99M"};
for (int i = 0; i < numbers.length; i++) {
int n = numbers[i];
String formatted = CurrencyUtils.getCompactStringForDisplay(n);
System.out.println(n + " => " + formatted);
assertEquals(expected[i], formatted);
}
}
}
回答by prateek Kanujiya
Please Convert your input in double and divide.
请将您的输入转换为双倍和除法。
回答by Adan Vivero
I mean it's quite simple. Set it as a double. So lets say
我的意思是这很简单。将其设置为双。所以让我们说
double answer = 3.0/2.0;
System.out.print(answer);
回答by Mohammad Zulfikar
You can do like,
你可以这样做，
int a = 3;
int b = 2;
int quotient = a / b;
int remainder = a % b;
To get quotient in real numbers
求实数商
System.out.println((double) a / b);
To get quotient in integer numbers
得到整数的商
System.out.println("Quotient: " + quotient);
System.out.println("Remainder: " + remainder);
To get quotient in real number such that one number after decimal
求实数中的商，使小数点后一位数
System.out.println(a / b + "." + a % b * 10 / b);
Note: In the last method it will not round the number up after the decimal.
注意：在最后一种方法中，它不会将小数点后的数字四舍五入。
