在 JavaScript 中增加日期
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Incrementing a date in JavaScript
提问by Santanu
I need to increment a date value by one day in JavaScript.
我需要在 JavaScript 中将日期值增加一天。
For example, I have a date value 2010-09-11 and I need to store the date of the next day in a JavaScript variable.
例如，我有一个日期值 2010-09-11，我需要将第二天的日期存储在 JavaScript 变量中。
How can I increment a date by a day?
如何将日期增加一天？
回答by T.J. Crowder
Three options for you:
三种方案供您选择：
1. Using just JavaScript's Dateobject (no libraries):
1. 只使用 JavaScript 的Date对象（没有库）：
My previous answer for #1 was wrong (it added 24 hours, failing to account for transitions to and from daylight saving time; Clever Humanpointed out that it would fail with November 7, 2010 in the Eastern timezone). Instead, Jigar's answeris the correct way to do this without a library:
我之前对 #1 的回答是错误的（它增加了 24 小时，没有考虑到夏令时的转换；Clever Human指出它会在东部时区的 2010 年 11 月 7 日失败）。相反，Jigar 的答案是在没有图书馆的情况下做到这一点的正确方法：
var tomorrow = new Date();
tomorrow.setDate(tomorrow.getDate() + 1);
This works even for the last day of a month (or year), because the JavaScript date object is smart about rollover:
这甚至适用于一个月（或一年）的最后一天，因为 JavaScript 日期对象在翻转方面很聪明：
var lastDayOf2015 = new Date(2015, 11, 31);
snippet.log("Last day of 2015: " + lastDayOf2015.toISOString());
var nextDay = new Date(+lastDayOf2015);
var dateValue = nextDay.getDate() + 1;
snippet.log("Setting the 'date' part to " + dateValue);
nextDay.setDate(dateValue);
snippet.log("Resulting date: " + nextDay.toISOString());<!-- Script provides the `snippet` object, see http://meta.stackexchange.com/a/242144/134069 -->
<script src="//tjcrowder.github.io/simple-snippets-console/snippet.js"></script>(This answer is currently accepted, so I can't delete it. Before it was accepted I suggested to the OP they accept Jigar's, but perhaps they accepted this one for items #2 or #3 on the list.)
（这个答案目前已被接受，所以我不能删除它。在它被接受之前，我建议 OP 他们接受 Jigar 的，但也许他们接受了这个列表中的第 2 项或第 3 项。）
2. Using MomentJS:
2. 使用MomentJS：
var today = moment();
var tomorrow = moment(today).add(1, 'days');
(Beware that addmodifies the instance you call it on, rather than returning a new instance, so today.add(1, 'days')would modify today. That's why we start with a cloning op on var tomorrow = ....)
（请注意，add修改您调用它的实例，而不是返回一个新实例，因此today.add(1, 'days')将修改today。这就是我们从 克隆操作开始的原因var tomorrow = ...。）
3. Using DateJS, but it hasn't been updated in a long time:
3.使用DateJS，但好久没更新了：
var today = new Date(); // Or Date.today()
var tomorrow = today.add(1).day();
回答by Jigar Joshi
var myDate = new Date();
//add a day to the date
myDate.setDate(myDate.getDate() + 1);
回答by CleverPatrick
None of the examples in this answer seem to work with Daylight Saving Time adjustment days. On those days, the number of hours in a day are not 24 (they are 23 or 25, depending on if you are "springing forward" or "falling back".)
此答案中的所有示例似乎都不适用于夏令时调整日。在那些日子里，一天中的小时数不是 24（它们是 23 或 25，取决于你是“向前”还是“后退”。）
The below AddDays javascript function accounts for daylight saving time:
下面的 AddDays javascript 函数说明了夏令时：
function addDays(date, amount) {
var tzOff = date.getTimezoneOffset() * 60 * 1000,
t = date.getTime(),
d = new Date(),
tzOff2;
t += (1000 * 60 * 60 * 24) * amount;
d.setTime(t);
tzOff2 = d.getTimezoneOffset() * 60 * 1000;
if (tzOff != tzOff2) {
var diff = tzOff2 - tzOff;
t += diff;
d.setTime(t);
}
return d;
}
Here are the tests I used to test the function:
以下是我用来测试该功能的测试：
var d = new Date(2010,10,7);
var d2 = AddDays(d, 1);
document.write(d.toString() + "<br />" + d2.toString());
d = new Date(2010,10,8);
d2 = AddDays(d, -1)
document.write("<hr /><br />" + d.toString() + "<br />" + d2.toString());
d = new Date('Sun Mar 27 2011 01:59:00 GMT+0100 (CET)');
d2 = AddDays(d, 1)
document.write("<hr /><br />" + d.toString() + "<br />" + d2.toString());
d = new Date('Sun Mar 28 2011 01:59:00 GMT+0100 (CET)');
d2 = AddDays(d, -1)
document.write("<hr /><br />" + d.toString() + "<br />" + d2.toString());
回答by Sylvain Lecorné
The easiest way is to convert to milliseconds and add 1000*60*60*24 milliseconds e.g.:
最简单的方法是转换为毫秒并添加 1000*60*60*24 毫秒，例如：
var tomorrow = new Date(today.getTime()+1000*60*60*24);
回答by jpmottin
Tomorrow in one line in pure JS but it's ugly!
明天在纯 JS 中一行，但它很丑！
new Date(new Date().setDate(new Date().getDate() + 1))
Here is the result :
结果如下：
Thu Oct 12 2017 08:53:30 GMT+0200 (Romance Summer Time)
回答by einarmagnus
You first need to parse your string before following the other people's suggestion:
在遵循其他人的建议之前，您首先需要解析您的字符串：
var dateString = "2010-09-11";
var myDate = new Date(dateString);
//add a day to the date
myDate.setDate(myDate.getDate() + 1);
If you want it back in the same format again you will have to do that "manually":
如果您希望它再次以相同的格式返回，则必须“手动”执行此操作：
var y = myDate.getFullYear(),
m = myDate.getMonth() + 1, // january is month 0 in javascript
d = myDate.getDate();
var pad = function(val) { var str = val.toString(); return (str.length < 2) ? "0" + str : str};
dateString = [y, pad(m), pad(d)].join("-");
But I suggest getting Date.js as mentioned in other replies, that will help you alot.
但是我建议按照其他回复中提到的方式获取 Date.js，这将对您有很大帮助。
回答by Polv
I feel that nothing is safer than .getTime()and .setTime(), so this should be the best, and performant as well.
我觉得没有什么比.getTime()and更安全的了.setTime()，所以这应该是最好的，也是性能最好的。
const d = new Date()
console.log(d.setTime(d.getTime() + 1000 * 60 * 60 * 24)) // MILLISECONDS
.setDate()for invalid Date (like 31 + 1) is too dangerous, and it depends on the browser implementation.
.setDate()对于无效日期（如 31 + 1）太危险了，这取决于浏览器的实现。
回答by fitodac
Getting the next 5 days:
获得接下来的 5 天：
var date = new Date(),
d = date.getDate(),
m = date.getMonth(),
y = date.getFullYear();
for(i=0; i < 5; i++){
var curdate = new Date(y, m, d+i)
console.log(curdate)
}
回答by Laksh Goel
Two methods:
两种方法：
1:
1：
var a = new Date()
// no_of_days is an integer value
var b = new Date(a.setTime(a.getTime() + no_of_days * 86400000)
2: Similar to the previous method
2：与之前的方法类似
var a = new Date()
// no_of_days is an integer value
var b = new Date(a.setDate(a.getDate() + no_of_days)
回答by swirekx
Date.prototype.AddDays = function (days) {
days = parseInt(days, 10);
return new Date(this.valueOf() + 1000 * 60 * 60 * 24 * days);
}
Example
例子
var dt = new Date();
console.log(dt.AddDays(-30));
console.log(dt.AddDays(-10));
console.log(dt.AddDays(-1));
console.log(dt.AddDays(0));
console.log(dt.AddDays(1));
console.log(dt.AddDays(10));
console.log(dt.AddDays(30));
Result
结果
2017-09-03T15:01:37.213Z
2017-09-23T15:01:37.213Z
2017-10-02T15:01:37.213Z
2017-10-03T15:01:37.213Z
2017-10-04T15:01:37.213Z
2017-10-13T15:01:37.213Z
2017-11-02T15:01:37.213Z
