xcode 格式字符串未使用数据参数
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Data argument not used by format string
提问by Try to be a success
following the videos on lynda's objective c i've ran intro a small problem,
按照 lynda 的目标 c 上的视频，我遇到了一个小问题，
#import <Foundation/Foundation.h>
#import "Player.h"
int main(int argc, const char * argv[])
{
@autoreleasepool {
Player *p = [[Player alloc] init];
NSLog(@"The score is @i", [p score]); <-- Data argument not used by format string
}
return 0;
}
回答by rmaddy
You don't have a valid format string. You want %i, not @i.
您没有有效的格式字符串。你想要%i，没有@i。
回答by Anoop Vaidya
Use NSLog(@"The score is %i", [p score]);
用 NSLog(@"The score is %i", [p score]);
scorereturns integer so %ior %dshould be used not @i
score返回整数所以%i或%d不应该使用@i
回答by nkongara
If value returned by [p score] is an integer then it should be
NSLog(@"The score is %i", [p score]); // Always use '%' as format specifier not '@'
如果 [p score] 返回的值是一个整数，那么它应该是
NSLog(@"The score is %i", [p score]); // 始终使用 '%' 作为格式说明符而不是 '@'
回答by leorleor
The format string should use %iinstead of @i:
格式字符串应该使用%i而不是@i：
NSLog(@"The score is %i", [p score]);
