javascript 仅当包含的字符串长度大于 X 时才替换
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Replace only if the containing string length is greater than X
提问by Iryn
I've a regex that will only match one character of the strings. I want to test the lentgh of its containing stringand if it was greater than 4 then make the replacement. For example, the regex is /\d/. I want to use the functional form of replace to match 12345but not 1234.
我有一个只匹配字符串中的一个字符的正则表达式。我想测试其包含字符串的长度，如果它大于 4，则进行替换。例如，正则表达式是/\d/. 我想使用 replace 的功能形式来匹配12345但不是1234.
Something like:
就像是：
text.replace(regex, function(match) {
if (STRING.length > 4)
return replacement
else
return match;
});
Note:/\d/is just an example. I didn't mention the real regex to focus on my real question, illustrated above.
注意：/\d/只是一个例子。我没有提到真正的正则表达式来关注我真正的问题，如上所示。
回答by Christiaan
Or if you want to do it that way:
或者，如果您想这样做：
function replaceWithMinLength (str, minLength) {
str.replace(/\w+/, function(match) {
if (match.length > minLength) {
return match;
} else {
return str;
}
});
}
回答by oomlaut
You're putting the horse before the cart. You would be better off:
你把马放在手推车之前。你会更好：
if(string.length > 4) {
string.replace('needle','replacement');
}
回答by Ry-
So by “containing string”, you mean like the same sequence of digits? Match them all at once:
那么“包含字符串”是指相同的数字序列吗？同时匹配它们：
text.replace(/\d{5,}/g, function(string) {
return string.replace(/\d/g, function(match) {
return replacement;
});
});
For example. The \d{5,}can easily be adapted to any type of string-thing.
例如。将\d{5,}可以很容易地适用于任何类型的字符串的东西。
