php 如何获取数组中键的位置
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How to get the position of a key within an array
提问by SoLoGHoST
Ok, so I need to grab the position of 'blah' within this array (position will not always be the same). For example:
好的，所以我需要在这个数组中获取 'blah' 的位置（位置并不总是相同的）。例如：
$array = (
'a' => $some_content,
'b' => $more_content,
'c' => array($content),
'blah' => array($stuff),
'd' => $info,
'e' => $more_info,
);
So, I would like to be able to return the number of where the 'blah' key is located at within the array. In this scenario, it should return 3. How can I do this quickly? And without affecting the $array array at all.
所以，我希望能够返回数组中“blah”键所在位置的数量。在这种情况下，它应该返回 3。我怎样才能快速做到这一点？并且根本不影响 $array 数组。
回答by zerkms
$i = array_search('blah', array_keys($array));
回答by hakre
If you know the key exists:
如果您知道密钥存在：
PHP 5.4 (Demo):
PHP 5.4（演示）：
echo array_flip(array_keys($array))['blah'];
PHP 5.3:
PHP 5.3：
$keys = array_flip(array_keys($array));
echo $keys['blah'];
If you don't know the key exists, you can check with isset:
如果您不知道密钥存在，您可以检查isset：
$keys = array_flip(array_keys($array));
echo isset($keys['blah']) ? $keys['blah'] : 'not found' ;
This is merely like array_searchbut makes use of the map that exists already inside any array. I can't say if it's really better than array_search, this might depend on the scenario, so just another alternative.
这只不过array_search是利用了已经存在于任何数组中的映射。我不能说它是否真的比 更好array_search，这可能取决于场景，所以只是另一种选择。
回答by Pranav Hosangadi
$keys=array_keys($array);will give you an array containing the keys of $array
$keys=array_keys($array);会给你一个包含键的数组 $array
So, array_search('blah', $keys);will give you the index of blahin $keysand therefore, $array
所以，array_search('blah', $keys);会给你blahin的索引，$keys因此，$array
