Javascript URI 正则表达式：如果 URL 有效，则将 http://、https://、ftp:// 替换为空字符串
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URI Regex: Replace http://, https://, ftp:// with empty string if URL valid
提问by jQuerybeast
I have a simple URL validator. The url validator works as probably every other validator.
我有一个简单的 URL 验证器。url 验证器可能像其他所有验证器一样工作。
Now I want, if the URL passed, take the https://, http:// and remove it for var b.
现在我想要，如果 URL 被传递，则使用 https://、http:// 并将其删除为var b.
So what I've done is I made a another Regex which captures https://, http://, ftp:// etc and say if the url passed the long test, get the second test and replace it with empty string.
所以我所做的是我制作了另一个正则表达式，它捕获 https://、http://、ftp:// 等，并说如果 url 通过了长时间测试，则获取第二个测试并将其替换为空字符串。
Here is what I came up with:
这是我想出的：
$("button").on('click', function () {
var url = $('#in').val();
var match = /^([a-z][a-z0-9\*\-\.]*):\/\/(?:(?:(?:[\w\.\-\+!$&'\(\)*\+,;=]|%[0-9a-f]{2})+:)*(?:[\w\.\-\+%!$&'\(\)*\+,;=]|%[0-9a-f]{2})+@)?(?:(?:[a-z0-9\-\.]|%[0-9a-f]{2})+|(?:\[(?:[0-9a-f]{0,4}:)*(?:[0-9a-f]{0,4})\]))(?::[0-9]+)?(?:[\/|\?](?:[\w#!:\.\?\+=&@!$'~*,;\/\(\)\[\]\-]|%[0-9a-f]{2})*)?$/;
var protomatch = /^(https?|ftp):\/\/(.*)/;
if (match.test(url)) { // IF VALID
console.log(url + ' is valid');
// if valid replace http, https, ftp etc with empty
var b = url.replace(protomatch.test(url), '');
console.log(b)
} else { // IF INVALID
console.log('not valid')
}
});
Why this doesn't work?
为什么这不起作用？
回答by YuS
var b = url.substr(url.indexOf('://')+3);
回答by Alnitak
protomatch.test()returns a boolean, not a string.
protomatch.test()返回一个布尔值，而不是一个字符串。
I think you just want:
我想你只是想要：
var protomatch = /^(https?|ftp):\/\//; // NB: not '.*'
...
var b = url.replace(protomatch, '');
FWIW, your matchregexp is completely impenetrable, and almost certainly wrong. It probably doesn't permit internationalised domains, but it's so hard to read that I can't tell for sure.
FWIW，您的正则match表达式完全无法理解，而且几乎肯定是错误的。它可能不允许国际化域，但它很难阅读，我无法确定。
回答by cregox
If you want a more generic approach, like Yuri's, but which will work for more cases:
如果您想要更通用的方法，例如 Yuri 的方法，但适用于更多情况：
var b = url.replace(/^.*:\/\//i, '');
回答by Tom
There may be an empty protocol, like: //example.com, so relying on '://' may not cover all cases.
可能有一个空协议，例如：//example.com，因此依赖 '://' 可能无法涵盖所有情况。
