在 SQL 2008 中获取最后一个 indexof 字符的最佳方法是什么
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What is best way to get last indexof character in SQL 2008
提问by Mahender
In C#, we have String.LastIndexOf
method to get a last index of a particular character location for given string. Is there any similar function to do same in SQL Server. I tried using CHARINDEX
but couldn't able to achieve it.
在 C# 中,我们有String.LastIndexOf
方法获取给定字符串的特定字符位置的最后一个索引。在 SQL Server 中是否有类似的功能可以做同样的事情。我尝试使用CHARINDEX
但无法实现。
回答by antinescience
A little tricky, but you could do something like:
有点棘手,但您可以执行以下操作:
REVERSE(SUBSTRING(REVERSE([field]),0,CHARINDEX('[char]',REVERSE([field]))))
回答by Aaron Bertrand
DECLARE @x VARCHAR(32) = 'xyzxyzyyythgetdghydgsh';
SELECT LEN(@x) - CHARINDEX('y', REVERSE(@x)) + 1;
回答by ljh
Try this one out, analyze result step by step.
试试这个,一步一步分析结果。
declare @string varchar(max)
declare @subString varchar(max)
set @string = 'this is a duplicated question, but may get some new answers, since tech chagne from time to time as we know';
set @subString = 'this is a duplicated question, but may get some new answers, since tech chagne from time to time'
--Find the string.lastIndexof(time)
select LEN(@String)
select LEN(@SubString)
select CHARINDEX('time', REVERSE(@string))
select reverse(@string)
select reverse('time')
SELECT LEN(@string) - CHARINDEX(reverse('time'), REVERSE(@string)) - Len('time') + 1