如何在 Python 中使用 -p 选项运行 os.mkdir()？
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How to run os.mkdir() with -p option in Python?
提问by pynovice
I want to run mkdircommand as:
我想运行mkdir命令：
mkdir -p directory_name
What's the method to do that in Python?
在 Python 中这样做的方法是什么？
os.mkdir(directory_name [, -p]) didn't work for me.
采纳答案by Adem ?zta?
You can try this:
你可以试试这个：
# top of the file
import os
import errno
# the actual code
try:
os.makedirs(directory_name)
except OSError as exc:
if exc.errno == errno.EEXIST and os.path.isdir(directory_name):
pass
回答by singer
Something like this:
像这样的东西：
if not os.path.exists(directory_name):
os.makedirs(directory_name)
UPD: as it is said in a comments you need to check for exception for thread safety
UPD：正如评论中所说，您需要检查线程安全的异常
try:
os.makedirs(directory_name)
except OSError as err:
if err.errno!=17:
raise
回答by pitfall
how about this
os.system('mkdir -p %s' % directory_name )
这个怎么样
os.system('mkdir -p %s' % directory_name )
回答by Michael Ma
According to the documentation, you can now use this since python 3.2
根据文档，您现在可以从 python 3.2 开始使用它
os.makedirs("/directory/to/make", exist_ok=True)
and it will not throw an error when the directory exists.
并且当目录存在时它不会抛出错误。
回答by Boris
If you're using pathlib, use Path.mkdir(parents=True, exist_ok=True)
如果您正在使用pathlib，请使用Path.mkdir(parents=True, exist_ok=True)
from pathlib import Path
new_directory = Path('./some/nested/directory')
new_directory.mkdir(parents=True, exist_ok=True)
parents=Truecreates parent directories as needed
parents=True根据需要创建父目录
exist_ok=Truetells mkdir()to not error if the directory already exists
exist_ok=Truemkdir()如果目录已经存在，则告诉不要出错
See the pathlib.Path.mkdir()docs.
