java 使用 Spring Rest 服务时在 Date 中获取错误的时间
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Getting wrong time in Date while using Spring Rest Service
提问by Srinu
This is my pojo class
这是我的 pojo 课
public class TeTripCarDtl implements Serializable {
private static final long serialVersionUID = -7601044160087552575L;
@Id
@Column(name = "CAR_ID")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long carId;
@Column(name = "TRIP_ID")
private long tripId;
@Column(name = "VEHICLE_TYPE")
private String vehicleType;
@JsonFormat(pattern = "yyyy-MM-dd'T'HH:mm:ss", shape = JsonFormat.Shape.STRING)
@Temporal(TemporalType.TIMESTAMP)
@Column(name = "PICKUP_DATE_TIME")
private Date pickUpDateTime;// Here I am getting wrong time value
@Temporal(value = TemporalType.TIMESTAMP)
@JsonFormat(pattern = "yyyy-MM-dd'T'HH:mm:ss", shape = JsonFormat.Shape.STRING)
@Column(name = "RETURN_DATE_TIME")
private Date returnDateTime;// Here I am getting wrong time value
@Column(name = "PICK_UP_LOCATION")
private String pickUpLocation;
@Column(name = "DROP_OFF_LOCATION")
private String dropOffLocation;
@Column(name = "CONFIRMED_SPECIAL_EQUIP")
private String confirmedSpecialEquip;
@Column(name = "LAST_UPDATED_BY")
private String lastUpdatedBy;
@Temporal(TemporalType.DATE)
@Column(name = "LAST_UPDATED_ON")
private Date lastUpdatedOn;
@Temporal(TemporalType.DATE)
@Column(name = "BOOKING_DATE")
private Date bookingDate;
@Column(name = "STATUS")
private String status;
public long getCarId() {
return carId;
}
public void setCarId(long carId) {
this.carId = carId;
}
public long getTripId() {
return tripId;
}
public void setTripId(long tripId) {
this.tripId = tripId;
}
public String getVehicleType() {
return vehicleType;
}
public void setVehicleType(String vehicleType) {
this.vehicleType = vehicleType;
}
public Date getPickUpDateTime() {
return pickUpDateTime;
}
public void setPickUpDateTime(Date pickUpDateTime) {
this.pickUpDateTime = pickUpDateTime;
}
public Date getReturnDateTime() {
return returnDateTime;
}
public void setReturnDateTime(Date returnDateTime) {
this.returnDateTime = returnDateTime;
}
public String getPickUpLocation() {
return pickUpLocation;
}
public void setPickUpLocation(String pickUpLocation) {
this.pickUpLocation = pickUpLocation;
}
public String getDropOffLocation() {
return dropOffLocation;
}
public void setDropOffLocation(String dropOffLocation) {
this.dropOffLocation = dropOffLocation;
}
public String getConfirmedSpecialEquip() {
return confirmedSpecialEquip;
}
public void setConfirmedSpecialEquip(String confirmedSpecialEquip) {
this.confirmedSpecialEquip = confirmedSpecialEquip;
}
public String getLastUpdatedBy() {
return lastUpdatedBy;
}
public void setLastUpdatedBy(String lastUpdatedBy) {
this.lastUpdatedBy = lastUpdatedBy;
}
public Date getLastUpdatedOn() {
return lastUpdatedOn;
}
public void setLastUpdatedOn(Date lastUpdatedOn) {
this.lastUpdatedOn = lastUpdatedOn;
}
public Date getBookingDate() {
return bookingDate;
}
public void setBookingDate(Date bookingDate) {
this.bookingDate = bookingDate;
}
public String getStatus() {
return status;
}
public void setStatus(String status) {
this.status = status;
}
@Override
public String toString() {
return "TeTripCarDtl [carId=" + carId + ", tripId=" + tripId + ", vehicleType=" + vehicleType
+ ", pickUpDateTime=" + pickUpDateTime + ", returnDateTime=" + returnDateTime + ", pickUpLocation="
+ pickUpLocation + ", dropOffLocation=" + dropOffLocation + ", confirmedSpecialEquip="
+ confirmedSpecialEquip + ", lastUpdatedBy=" + lastUpdatedBy + ", lastUpdatedOn=" + lastUpdatedOn
+ ", bookingDate=" + bookingDate + ", status=" + status + "]";
}
}
Input json
输入json
{"vehicleType":"ECAR","pickUpDateTime":"2017-06-10T07:30:04", "returnDateTime":"2017-06-10T07:30:04","pickUpLocation":"PNQ","dropOffLocation":"BOM","confirmedSpecialEquip":"HCL,TCS,INFO","status":"BOOKED"}
Spring Restcontroller class
Spring Restcontroller 类
@RestController
public class DateControllerTest {
@RequestMapping(value="date_test", method = RequestMethod.POST)
public String reciveData(@RequestBody TeTripCarDtl teTripCarDtl){
System.out.println("PickUpDateAndTime:"+teTripCarDtl.getPickUpDateTime()+","
+ "ReturnDateAndTime:"+teTripCarDtl.getReturnDateTime());
return "recived";
}
}
I am printing date values in console it it is printing like this .Here I am getting time is wrong, I suppose to get time 07:30:04but I am getting 13:00:04except this everything is fine
我正在控制台中打印日期值，它是这样打印的。在这里我得到的时间是错误的，我想得到时间07:30:04但我得到13:00:04除了这一切都很好
PickUpDateAndTime:Sat Jun 10 13:00:04 IST 2017,ReturnDateAndTime:Sat Jun 10 13:00:04 IST 2017
Please help me with this.
请帮我解决一下这个。
采纳答案by Sangam Belose
The @JsonFormat annotations have timeZone issues. Please check the link for more details on issue.Hymanson-data-bind issueOverriding the timezone in ObjectMapper didnt worked either. I have solved the problem by implementing custom Date Deserializer as below:
@JsonFormat 注释有 timeZone 问题。请查看链接以获取有关问题的更多详细信息。Hymanson-data-bind 问题覆盖 ObjectMapper 中的时区也不起作用。我通过实现自定义日期反序列化器解决了这个问题，如下所示：
@Component
public class CustomDateDeserializer extends StdDeserializer<Date> {
/**
*
*/
private static final long serialVersionUID = 1L;
private SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss"); // specify your specific timezone
public CustomDateDeserializer() {
this(null);
}
public CustomDateDeserializer(Class<?> vc) {
super(vc);
}
@Override
public Date deserialize(JsonParser jsonparser, DeserializationContext context)
throws IOException, JsonProcessingException {
String date = jsonparser.getText();
try {
return formatter.parse(date);
} catch (ParseException e) {
throw new RuntimeException(e);
}
}
}
and then apply the deserializer on setter method of your bean properties.
然后在 bean 属性的 setter 方法上应用反序列化器。
@JsonDeserialize(using = CustomDateDeserializer.class)
public void setReturnDateTime(Date returnDateTime) {
this.returnDateTime = returnDateTime;
}
similarly you can implement your custom serializer for vice versa operation.
同样，您可以实现您的自定义序列化程序，反之亦然。
回答by Daniel Higueras
The Hymanson @JsonFormatannotation has a specific timezoneattribute. If you specify the timezone you wish to use, you can fix this issue.
Hymanson@JsonFormat注释有一个特定的timezone属性。如果您指定要使用的时区，则可以解决此问题。
Example:
例子：
@JsonFormat(pattern = "yyyy-MM-dd'T'HH:mm:ss", timezone = "Europe/Madrid")
参考：http: //fasterxml.github.io/Hymanson-annotations/javadoc/2.1.0/com/fasterxml/Hymanson/annotation/JsonFormat.html
回答by talalUcef
I had the same problem before, it's a time zone problem, so I convert my date to string before sending, you can use this function to convert date to string :
我以前遇到过同样的问题，这是一个时区问题，所以我在发送之前将日期转换为字符串，您可以使用此函数将日期转换为字符串：
public static String dateFormatString(Date date, String pattern) {
if (date != null) {
SimpleDateFormat formatter = new SimpleDateFormat(pattern);
return formatter.format(date);
}
return null;
}
for the pattern you can use : yyyy-MM-dd HH:mm:ss
对于您可以使用的模式：yyyy-MM-dd HH:mm:ss
回答by Issam EL-ATIF
It is a time zone issue. When you don't specify a timezone Hymanson consider that date is in UTC time and convert it to your default locale which is IST. As you can see 07:30:04 UTCis equivalent to 13:00:04 IST.
这是一个时区问题。当您不指定时区时，Hymanson 考虑该日期是 UTC 时间并将其转换为您的默认语言环境，即 IST。如您所见07:30:04 UTC相当于13:00:04 IST。
You can specify timezone in input json like this "pickUpDateTime":"2017-06-10T07:30:04.000+05:30"hence IST=UTC+5:30
您可以像这样在输入 json 中指定时区，"pickUpDateTime":"2017-06-10T07:30:04.000+05:30"因此 IST=UTC+5:30
