Html 使用 css 在 img 标签上渐变

Gradient over img tag using css

提问by Aliaksei Maroz

I want to place a gradient over an <img>tag. srcattribute of the tag is angular-item. For example: <img src={{value.angitem.image}}>

我想在<img>标签上放置一个渐变。src标签的属性是angular-item。例如： <img src={{value.angitem.image}}>

I've tried to make css class:

我试图制作 css 类：

.pickgradient {
    background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(0,0,0,0)), color-stop(100%,rgba(0,0,0,0.65)));
}

and

和

<img src={{value.angitem.image}} class="pickgradient ">

but it doesn't work. What should I do?

但它不起作用。我该怎么办？

回答by web-tiki

With z-index :

使用 z-index ：

You may use a container and put the gradient on that container. Then use a negative z-index to position image behind the gradient.

您可以使用容器并将渐变放在该容器上。然后使用负 z-index 将图像定位在渐变后面。

.pickgradient {
  display:inline-block;
  background: -moz-linear-gradient(top, rgba(0,0,0,0) 0%, rgba(0,0,0,0.65) 100%); /* FF3.6+ */
  background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(0,0,0,0.65)), color-stop(100%,rgba(0,0,0,0))); /* Chrome,Safari4+ */
  background: -webkit-linear-gradient(top, rgba(0,0,0,0) 0%,rgba(0,0,0,0.65) 100%); /* Chrome10+,Safari5.1+ */
  background: -o-linear-gradient(top, rgba(0,0,0,0) 0%,rgba(0,0,0,0.65) 100%); /* Opera 11.10+ */
  background: -ms-linear-gradient(top, rgba(0,0,0,0) 0%,rgba(0,0,0,0.65) 100%); /* IE10+ */
  background: linear-gradient(to bottom, rgba(0,0,0,0) 0%,rgba(0,0,0,0.65) 100%); /* W3C */
  filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#a6000000', endColorstr='#00000000',GradientType=0 ); /* IE6-9 */
}

img{
  position:relative;
  z-index:-1;
  display:block;
  height:200px; width:auto;
}

<div class="pickgradient">
  <img src="http://i.imgur.com/HDssntn.jpg" />
</div>

---

---

With a pseudo element :

使用伪元素：

As commented, you can also use a pseudo element with the gradient and absolute positioning to put the gradient over the image:

正如所评论的，您还可以使用具有渐变和绝对定位的伪元素将渐变放在图像上：

.pickgradient{
  position:relative;
  display:inline-block;
}
.pickgradient:after {
  content:'';
  position:absolute;
  left:0; top:0;
  width:100%; height:100%;
  display:inline-block;
  background: -moz-linear-gradient(top, rgba(0,0,0,0) 0%, rgba(0,0,0,0.65) 100%); /* FF3.6+ */
  background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(0,0,0,0.65)), color-stop(100%,rgba(0,0,0,0))); /* Chrome,Safari4+ */
  background: -webkit-linear-gradient(top, rgba(0,0,0,0) 0%,rgba(0,0,0,0.65) 100%); /* Chrome10+,Safari5.1+ */
  background: -o-linear-gradient(top, rgba(0,0,0,0) 0%,rgba(0,0,0,0.65) 100%); /* Opera 11.10+ */
  background: -ms-linear-gradient(top, rgba(0,0,0,0) 0%,rgba(0,0,0,0.65) 100%); /* IE10+ */
  background: linear-gradient(to bottom, rgba(0,0,0,0) 0%,rgba(0,0,0,0.65) 100%); /* W3C */
  filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#a6000000', endColorstr='#00000000',GradientType=0 ); /* IE6-9 */
}

img{
  display:block;
  height:200px;width:auto;
}

<div class="pickgradient">
  <img src="http://i.imgur.com/HDssntn.jpg" />
</div>

回答by KnightHawk

try placing a divover the image in question and placing the gradient on the div instead of the image.

尝试将 adiv放在有问题的图像上，并将渐变放在 div 而不是图像上。