如何在Java中生成随机正负数
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How to generate random positive and negative numbers in Java
提问by user455497
I am trying to generate random integers over the range (-32768, 32767) of the primitive data type short. The java Random object only generates positive numbers. How would I go about randomly creating numbers on that interval? Thanks.
我正在尝试在原始数据类型 short 的范围 (-32768, 32767) 内生成随机整数。java Random 对象只生成正数。我将如何在该时间间隔内随机创建数字？谢谢。
采纳答案by pinichi
You random on (0, 32767+32768)then subtract by 32768
你随机(0, 32767+32768)然后减去32768
回答by jcopenha
Generate numbers between 0 and 65535 then just subtract 32768
生成 0 到 65535 之间的数字，然后减去 32768
回答by duggu
public static int generatRandomPositiveNegitiveValue(int max , int min) {
//Random rand = new Random();
int ii = -min + (int) (Math.random() * ((max - (-min)) + 1));
return ii;
}
回答by Truth
Random random=new Random();
int randomNumber=(random.nextInt(65536)-32768);
回答by Ethan
This is an old question I know but um....
这是一个我知道的老问题，但嗯....
n=n-(n*2)
回答by UP209D
(Math.floor((Math.random() * 2)) > 0 ? 1 : -1) * Math.floor((Math.random() * 32767))
(Math.floor((Math.random() * 2)) > 0 ? 1 : -1) * Math.floor((Math.random() * 32767))
回答by Brian
In case folks are interested in the double version (note this breaks down if passed MAX_VALUE or MIN_VALUE):
如果人们对双版本感兴趣（请注意，如果通过 MAX_VALUE 或 MIN_VALUE，这会崩溃）：
private static final Random generator = new Random();
public static double random(double min, double max) {
return min + (generator.nextDouble() * (max - min));
}
回答by Russ Hymanson
([my double-compatible primitive type here])(Math.random() * [my max value here] * (Math.random() > 0.5 ? 1 : -1))
([我的双重兼容原始类型])(Math.random() * [我的最大值] * (Math.random() > 0.5 ? 1 : -1))
example:
例子：
// need a random number between -500 and +500
long myRandomLong = (long)(Math.random() * 500 * (Math.random() > 0.5 ? 1 : -1));
