C# 如何使用 GetEnumerator() 实现 IEnumerable<T>？

How to implement IEnumerable<T> with GetEnumerator()?

提问by Colonel Panic

I would like my type to implement IEnumerable<string>. I tried to follow C# in a Nutshell, but something went wrong:

我希望我的类型实现IEnumerable<string>. 我试图在 Nutshell 中遵循 C#，但出了点问题：

public class Simulation : IEnumerable<string>
{
    private IEnumerable<string> Events()
    {
        yield return "a";
        yield return "b";
    }

    public IEnumerator<string> GetEnumerator()
    {
        return Events().GetEnumerator();
    }
}

But I get the build error

但我收到构建错误

Error 1 'EventSimulator.Simulation' does not implement interface member 'System.Collections.IEnumerable.GetEnumerator()'. 'EventSimulator.Simulation.GetEnumerator()' cannot implement 'System.Collections.IEnumerable.GetEnumerator()' because it does not have the matching return type of 'System.Collections.IEnumerator'.

错误 1 ​​'EventSimulator.Simulation' 未实现接口成员 'System.Collections.IEnumerable.GetEnumerator()'。“EventSimulator.Simulation.GetEnumerator()”无法实现“System.Collections.IEnumerable.GetEnumerator()”，因为它没有“System.Collections.IEnumerator”的匹配返回类型。

采纳答案by Filip Ekberg

You're missing IEnumerator IEnumerable.GetEnumerator():

你失踪了IEnumerator IEnumerable.GetEnumerator()：

public class Simulation : IEnumerable<string>
{
    private IEnumerable<string> Events()
    {
        yield return "a";
        yield return "b";
    }

    public IEnumerator<string> GetEnumerator()
    {
        return Events().GetEnumerator();
    }

    IEnumerator IEnumerable.GetEnumerator()
    {
        return GetEnumerator();
    }
}

回答by NominSim

IEnumerable requires that you implement both the typed and generic method.

IEnumerable 要求您实现类型化和泛型方法。

In the community section of the msdn docsit explains why you need both. (For backwards compatibility is the reason given essentially).

在 msdn文档的社区部分，它解释了为什么您需要两者。（为了向后兼容是本质上给出的原因）。