Bash：检查主机名是否为 vq* 如何使用通配符？
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Bash: check if hostname is v-q* how to use wildcards?
提问by BoDiE2003
I have the next code and I need it to echo 1 if the hostname matches with v-qai01 or any other v-q* servers:
我有下一个代码，如果主机名与 v-qai01 或任何其他 vq* 服务器匹配，我需要它来回显 1：
if [ `hostname -s` -eq `v-q*` ]; then
echo "1"
fi
Im having several errors:
我有几个错误：
./run.sh: line 3: v-q*: command not found
./run.sh: line 3: [: v-qai01: unary operator expected
Any suggestions please?
请问有什么建议吗？
What if I have the next case?
如果我有下一个案例怎么办？
hostname=`hostname -s`
portalesWildcard=v-*ws*
qaiservers={'v-qai01' 'v-qai02'}
portales={'t1wsyellar01' }
if [[ ${hostname} = ${qaiservers} ]]; then
echo "yes"
fi
Thanks
谢谢
回答by John Kugelman
Use double square brackets and the =operator will accept wildcards:
使用双方括号，=运算符将接受通配符：
#!/bin/bash
if [[ $(hostname -s) = v-q* ]]; then
...
fi
It also has a =~operator for regex matches when you need more advanced string matching. This would check that the host name also ends with one or more digits:
=~当您需要更高级的字符串匹配时，它还具有用于正则表达式匹配的运算符。这将检查主机名是否也以一位或多位数字结尾：
#!/bin/bash
if [[ $(hostname -s) =~ ^v-q.*[0-9]+$ ]]; then
...
fi
回答by glenn Hymanman
you can use the casestatement:
您可以使用以下case语句：
case $(hostname -s) in
v-q*) echo yes ;;
*) echo no ;;
esac
回答by Ms CodeGuru
The actual problem that the original poster had was that they used backticks around the string:
原始海报的实际问题是他们在字符串周围使用了反引号：
if [ `hostname -s` -eq `v-q*` ]; then
rather than string quotes. Backticks tell the shell to execute the string within them as a command. In this case, the shell tried to execute:
而不是字符串引号。反引号告诉 shell 将其中的字符串作为命令执行。在这种情况下，shell 尝试执行：
v-q*
which failed.
哪个失败了。
回答by Bryan Drewery
This will remove v-qfrom the beginning of the string. If the condition is true, your hostname matches v-q*
这将从v-q字符串的开头删除。如果条件为真，则您的主机名匹配v-q*
hostname=`hostname -s`
if ! [ "${hostname#v-q}" = "${hostname}" ]; then
echo "1"
fi
