bash 将元素添加到数组中
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Add element into Array
提问by paul
I′m trying to dynamically add an element into an array:
我正在尝试将一个元素动态添加到数组中：
array=("element1" "element2" "element3")
fa=()
# now loop through the above array
for i in "${array[@]}"
do
fa+=("$i")
# or do whatever with individual element of the array
done
echo $fa
But it's returning element1.
但它回来了element1。
I've tried with an index, but I'm getting the same result:
我尝试使用索引，但得到相同的结果：
fa[index]="$i"
((index++))
Am I doing something wrong here?
我在这里做错了吗？
回答by sjsam
The problem is with printing ie echo $fa. This is equivalent to echo ${fa[0]}which means the first element of the array, so you gotelement1
问题出在打印 ie 上echo $fa。这相当于echo ${fa[0]}which 表示数组的第一个元素，所以你得到element1
echo "${fa[@]}"
should give you the entire array.
应该给你整个数组。
Reference
参考
[ This ]should give you a nice description about bash arrays.
[ 这个 ]应该给你一个关于 bash 数组的很好的描述。
