javascript express.js - 如何拦截 response.send() / response.json()
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express.js - how to intercept response.send() / response.json()
提问by pleerock
Lets say I have multiple places where I call response.send(someData). Now I want to create a single global interceptor where I catch all .sendmethods and make some changes to someData. Is there any way in express.js? (hooks, listeners, interceptors, ...)?
假设我有多个地方可以调用response.send(someData). 现在我想创建一个全局拦截器，我可以在其中捕获所有.send方法并对someData. express.js 有什么办法吗？（钩子，侦听器，拦截器，...）？
回答by Sami
You can define a middleware as below (taken and modified from this answer)
您可以定义一个中间件如下（从这个答案中获取和修改）
function modifyResponseBody(req, res, next) {
var oldSend = res.send;
res.send = function(data){
// arguments[0] (or `data`) contains the response body
arguments[0] = "modified : " + arguments[0];
oldSend.apply(res, arguments);
}
next();
}
app.use(modifyResponseBody);
回答by Don
Yes this is possible. There are two ways to do this, one is to use a library that provides the interception, with the ability to run it based on a specific condition: https://www.npmjs.com/package/express-interceptor
是的，这是可能的。有两种方法可以做到这一点，一种是使用提供拦截的库，并能够根据特定条件运行它：https: //www.npmjs.com/package/express-interceptor
The other option is to just create your own middleware (for express) as follows:
另一种选择是创建您自己的中间件（用于 express），如下所示：
function modify(req, res, next){
res.body = "this is the modified/new response";
next();
}
express.use(modify);
回答by cpri
for those finding on google, based off the top answer:
对于那些在谷歌上找到的人，基于最佳答案：
app.use((req, res, next) => {
let oldSend = res.send
res.send = function(data) {
console.log(data) // do something with the data
res.send = oldSend // set function back to avoid the 'double-send'
return res.send(data) // just call as normal with data
}
next()
})
