如何在 Java 中创建 ZIP 文件？
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How do I create a ZIP file in Java?
提问by Marcus Leon
What is the Java equivalent to this jar command:
与此 jar 命令等效的 Java 是什么：
C:\>jar cvf myjar.jar directory
I'd like to create this jar file programmatically as I can't be assured that the jarcommand will be on the system path where I could just run the external process.
我想以编程方式创建这个 jar 文件，因为我不能保证jar命令将在我可以运行外部进程的系统路径上。
Edit: All I want is to archive (and compress) a directory. Doesn't have to follow any java standard. Ie: a standard zip is fine.
编辑：我想要的只是存档（并压缩）一个目录。不必遵循任何 Java 标准。即：标准拉链很好。
回答by Romain Hippeau
// These are the files to include in the ZIP file
String[] source = new String[]{"source1", "source2"};
// Create a buffer for reading the files
byte[] buf = new byte[1024];
try {
// Create the ZIP file
String target = "target.zip";
ZipOutputStream out = new ZipOutputStream(new FileOutputStream(target));
// Compress the files
for (int i=0; i<source.length; i++) {
FileInputStream in = new FileInputStream(source[i]);
// Add ZIP entry to output stream.
out.putNextEntry(new ZipEntry(source[i]));
// Transfer bytes from the file to the ZIP file
int len;
while ((len = in.read(buf)) > 0) {
out.write(buf, 0, len);
}
// Complete the entry
out.closeEntry();
in.close();
}
// Complete the ZIP file
out.close();
} catch (IOException e) {
}
You can also use the answer from this post How to use JarOutputStream to create a JAR file?
您还可以使用这篇文章中的答案如何使用 JarOutputStream 创建 JAR 文件？
回答by whaley
Everything you'll want is in the java.util.jar package:
你想要的一切都在 java.util.jar 包中：
http://java.sun.com/javase/6/docs/api/java/util/jar/package-summary.html
http://java.sun.com/javase/6/docs/api/java/util/jar/package-summary.html
