php Laravel 5，如何测试控制器中是否选中了复选框
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Laravel 5, how to test if a Checkbox is checked in a controller
提问by loic.lopez
i tried to get if checkbox is checked with :
我试图了解是否选中了复选框：
In my view :
在我看来 ：
<form data-toggle="validator" data-disable="false" role="form" action="/admin/role/add" method="post">
<div class="checkbox checkbox-success">
<input name="test" id="test" type="checkbox" value="test">
<label for="test" style="padding-left: 15px!important;">test</label>
</div>
</form>
<form data-toggle="validator" data-disable="false" role="form" action="/admin/role/add" method="post">
{{ csrf_field() }}
<div class="form-group pull-right">
<button type="submit" class="btn btn-danger">Submit</button>
</div>
</form>
In my controller :
在我的控制器中：
public function createRole(Request $request)
{
if( $request->has('test')) {
new \App\Debug\Firephp('test', ['test' => true]);
}
}
in web.php :
在 web.php 中：
Route::post('/admin/role/add', 'AdminController@createRole')
but doesn't work.
但不起作用。
How i can do ?
我该怎么办？
Thanks for reply.
谢谢您的回复。
EDIT 1 :
编辑 1：
It was my form that was poorly build
是我的身体构造不佳
采纳答案by Ed Rands
I believe your real problem is that you have two separate forms. Your checkbox is in one form, your submit button is in a second form. I believe they both need to be in the same form. Otherwise your checkbox state is never returned, regardless of it's state.
我相信你真正的问题是你有两种不同的形式。你的复选框是一种形式，你的提交按钮是另一种形式。我相信它们都需要采用相同的形式。否则您的复选框状态永远不会返回，无论它的状态如何。
In your view, try replacing the form markup you provided with this:
在您看来，尝试替换您提供的表单标记：
<form data-toggle="validator" data-disable="false" role="form" action="/admin/role/add" method="post">
<div class="checkbox checkbox-success">
<input name="test" id="test" type="checkbox" value="test">
<label for="test" style="padding-left: 15px!important;">test</label>
</div>
{{ csrf_field() }}
<div class="form-group pull-right">
<button type="submit" class="btn btn-danger">Submit</button>
</div>
</form>
回答by Kurucu
You can test it with:
您可以使用以下方法对其进行测试：
if( Input::get('test', false) ) {
// there is something for 'test'
} else {
// there was no 'test' or it was false
}
Or
或者
if( Request::input('test') ) { //...
Or
或者
public function store(Request $request)
{
if( $request->has('test') ){
//...
}
}
回答by Peon
Checkbox sends info onlywhen it's checked, so what you do is, you check, if the value is present. It's easier, if you use method with Request $requestthan using direct inputs:
复选框仅在选中时发送信息，因此您要做的是检查该值是否存在。如果您使用方法 withRequest $request比使用直接输入更容易：
if (isset($request->test)) {
// checked
}
Laravel docs: https://laravel.com/docs/5.0/requests
Laravel 文档：https://laravel.com/docs/5.0/requests
回答by Zoran Stankovic
I made an class and put this method into it:
我做了一个类并将这个方法放入其中：
//This function is used to insert missing index key when checkboxes are used
public static function checkboxHelper($request_array, $key)
{
if(!array_key_exists($key,$request_array)){
$request_array[$key]=0;
}
else{
$request_array[$key]=1;
}
return $request_array;
}
This method is taking array from $request object and inserting missing key (name of checkbox).
此方法从 $request 对象中获取数组并插入缺少的键（复选框名称）。
