Jquery：Ajax 调用 servlet 并以 json 形式获取数据
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Jquery: Ajax call to servlet & get data as json
提问by DamnCoder
I'm newbie on servlet and I need to get data from database to display chart
我是 servlet 的新手，我需要从数据库中获取数据以显示图表
$.ajax({
url : "NameServlet",
dataType : 'json',
error : function(){
alert("Error Occured");
},
success : function(data) {
var receivedData = [];
//how to put data in var (i.e. receivedData) which is received from servlet
}
});
what would be my servletto get data
什么是我的servlet来获取数据
采纳答案by Rahul P
so here is the answer
所以这就是答案
you jquery to push data to your variable
你 jquery 将数据推送到你的变量
$.ajax({
url : "NameServlet",
dataType : 'json',
error : function() {
alert("Error Occured");
},
success : function(data) {
var receivedData = [];
$.each(data.jsonArray, function(index) {
$.each(data.jsonArray[index], function(key, value) {
var point = [];
point.push(key);
point.push(value);
receivedData.push(point);
});
});
}
});
after this you need servlet to get JSON object
在此之后，您需要 servlet 来获取 JSON 对象
Servlet would be like
Servlet 会像
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class NameServlet extends HttpServlet {
int []sampleData=null;
//sampleData= here you can get data from database
//writing data to json
response.setContentType("application/json;charset=utf-8");
JSONObject json = new JSONObject();
JSONArray array = new JSONArray();
JSONObject member = new JSONObject();
member.put("arrayData", sampleData);
array.add(member);
json.put("jsonArray", array);
PrintWriter pw = response.getWriter();
pw.print(json.toString());
pw.close();
}
Hope this helps
希望这可以帮助
