node.js fs 模块函数使用的当前目录是什么？
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What is the current directory used by fs module functions?
提问by Old Geezer
What is the current directory when a method in the fsmodule is invoked in a typical node.js/Express app? For example:
fs在典型的 node.js/Express 应用程序中调用模块中的方法时，当前目录是什么？例如：
var fs = require('fs');
var data = fs.readFile("abc.jpg", "binary");
What is the default folder used to locate abc.jpg? Is it dependent on the containing script's folder location?
用于定位 abc.jpg 的默认文件夹是什么？它是否取决于包含脚本的文件夹位置？
Is there a method to query the current directory?
有没有查询当前目录的方法？
My file structure is:
我的文件结构是：
ExpressApp1/
app.js
routes/
members.js
In members.js I have a fs.createWriteStream("abc")and file abcwas created in ExpressApp1/
在 members.js 我有一个fs.createWriteStream("abc")文件abc是在ExpressApp1/
回答by ardilgulez
It's the directory where the node interpreter was started from (aka the current working directory), not the directory of script's folder location (thank you robertklep).
它是节点解释器启动的目录（也称为当前工作目录），而不是脚本文件夹位置的目录（谢谢 robertklep）。
Also, current working directory can be obtained by:
此外，可以通过以下方式获取当前工作目录：
process.cwd()
For more information, you can check out: https://nodejs.org/api/fs.html
有关更多信息，您可以查看：https: //nodejs.org/api/fs.html
EDIT: Because you started app.js by node app.jsat ExpressApp1directory, every relative path will be relative to "ExpressApp1" folder, that's why fs.createWriteStream("abc")will create a write stream to write to a file in ExpressApp1/abc. If you want to write to ExpressApp1/routes/abc, you can change the code in members.jsto:
编辑：因为您通过node app.jsatExpressApp1目录启动 app.js ，所以每个相对路径都将相对于“ExpressApp1”文件夹，这就是为什么fs.createWriteStream("abc")要创建写入流以写入ExpressApp1/abc. 如果要写入ExpressApp1/routes/abc，可以将代码更改members.js为：
fs.createWriteStream(path.join(__dirname, "abc"));
For more:
更多信息：
https://nodejs.org/docs/latest/api/globals.html#globals_dirname
https://nodejs.org/docs/latest/api/globals.html#globals_dirname
https://nodejs.org/docs/latest/api/path.html#path_path_join_paths
https://nodejs.org/docs/latest/api/path.html#path_path_join_paths
