简单登录Java程序
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Simple login Java program
提问by Jesper Bruun Hansen
I'm very new to Java, and I want to make a very simple login Java-program. Don't think about security issues and such in this example, I just need help to get it right. My "Account informations" has to be stored in an Array.
我对 Java 很陌生，我想制作一个非常简单的登录 Java 程序。在这个例子中不要考虑安全问题等，我只需要帮助来解决它。我的“帐户信息”必须存储在一个数组中。
This is my code: -- MAIN --
这是我的代码：--主要--
import java.util.Scanner;
public class BATM {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String username;
String password;
System.out.println("Log in:");
System.out.println("Indtast username: ");
username = input.nextLine();
System.out.println("Indtast password: ");
password = input.nextLine();
users check = new users(username, password);
if(check.auth())
System.out.println("You are logged in");
}
}
-- users ---
-- 用户 ---
public class users {
private String username;
private String password;
private String[][] accounts = {{"jesper", "abc123"},{"christian", "abc123"}};
public users(String user, String pass){
username = user;
password = pass;
}
public boolean auth(){
if((username == accounts[0][0]) && (password == accounts[0][1]))
return true;
else
return false;
}
}
I guess this should be a quite simple function, but for some reason the if-statment will never return "true".
我想这应该是一个非常简单的函数，但由于某种原因，if 语句永远不会返回“true”。
What am I doing wrong?
我究竟做错了什么？
Jesper.
杰斯珀。
采纳答案by subash
try this..
尝试这个..
if((username.equals(accounts[0][0])) && (password.equals(accounts[0][1])))
回答by Uku Loskit
you are doing the string comparison wrong, in java you need to use .equals()isntead of ==the latter compares two object references, this is not what you want.
你做的字符串比较错误，在java中你需要使用
后者比较两个对象引用的.equals()isntead ==，这不是你想要的。
