java charAt() 无法使用数组提取单个成员
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charAt() unable to extract individual members with array
提问by Mahesh Bhagat
I have one array which is a fixed array. I have assigned some strings to it when it is created like:
我有一个数组，它是一个固定数组。我在创建时为其分配了一些字符串，例如：
String []alpha = new String[]{"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q"};
But it is giving me an error for this line:
但它给了我这一行的错误：
alpha.charAt(0); //error
I have also tried this with dynamic arrays where user is entering a string and I access the string with a userText variable:
我也用动态数组尝试过这个，用户输入一个字符串，我用一个 userText 变量访问这个字符串：
userText.charAt(i); //valid
Is this correct? I am not getting an error.
这个对吗？我没有收到错误。
回答by kosa
alpha.charAt(0);
alphais array, so you need to use index for lookup to get Stringand then get first character.
alpha是数组，因此您需要使用索引进行查找以获取String然后获取第一个字符。
Example:
例子：
alpha[0].chartAt(0);
Note: This is example only, make sure lengthand nullchecks are performed when you do index lookup.
注意：这仅仅是举例，确保length与null当你做索引查找进行检查。
There is not enough code in your question, but I guess userText.chartAt(i)not giving error because userTextis String.
您的问题中没有足够的代码，但我想userText.chartAt(i)不会给出错误，因为userTextis String。
