php 如何删除字符串中第一个特定字符之前的所有内容?
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How to remove everything before the first specific character in a string?
提问by Andrej
My variables look like this:
我的变量如下所示:
AAAAAAA, BB CCCCCCCC
AAAAAAA, BB CCCCCCCC
AAAA,BBBBBB CCCCCC
AAAA,BBBBBB CCCCCC
I would like to remove everything before the ",
",
我想删除“ ,
”之前的所有内容,
so the results should look like:
所以结果应该是这样的:
BB CCCCCCCC
BB CCCCCC
BBBBBB CCCCCC
BBBBBB中交
I have worked out this to remove everything AFTER the ",
":
我已经解决了这个问题,以删除“ ,
”之后的所有内容:
list($xxx) = explode(',', $yyyyy);
unfortunately I dont know how to get it to work to remove everything BEFORE the ",
".
不幸的是,我不知道如何让它工作以删除“ ,
”之前的所有内容。
回答by Andrew Moore
Since this is a simple string manipulation, you can use the following to remove all characters before the first comma:
由于这是一个简单的字符串操作,您可以使用以下命令删除第一个逗号之前的所有字符:
$string = preg_replace('/^[^,]*,\s*/', '', $input);
preg_replace()
allows you to replace parts of a string based on a regular expression. Let's take a look at the regular expression.
preg_replace()
允许您根据正则表达式替换部分字符串。我们来看看正则表达式。
/ is the start delimiter
^ is the "start of string" anchor
[^,] every character that isn't a comma (^ negates the class here)
* repeated zero or more times
, regular comma
\s any whitespace character
* repeated zero or more times
/ end delimiter
/ is the start delimiter
^ is the "start of string" anchor
[^,] every character that isn't a comma (^ negates the class here)
* repeated zero or more times
, regular comma
\s any whitespace character
* repeated zero or more times
/ end delimiter
回答by Tim Cooper
I wouldn't recommend using explode, as it causes more issues if there is more than one comma.
我不建议使用爆炸,因为如果有多个逗号,它会导致更多问题。
// removes everything before the first ,
$new_str = substr($str, ($pos = strpos($str, ',')) !== false ? $pos + 1 : 0);
Edit:
编辑:
if(($pos = strpos($str, ',')) !== false)
{
$new_str = substr($str, $pos + 1);
}
else
{
$new_str = get_last_word($str);
}
回答by nickf
list(,$xxx) = explode(',', $yyyyy, 2);
回答by Lawrence Cherone
try this it gets the last stuff after the , if no , is present it will check from the last space, i wrapped it in a function to make it easy:
试试这个,它获取 之后的最后一个东西,如果没有,它会从最后一个空间检查,我把它包装在一个函数中以使其容易:
<?php
$value='AAAA BBBBBB CCCCCC';
function checkstr($value){
if(strpos($value,',')==FALSE){
return trim(substr(strrchr($value, ' '), 1 ));
}else{
return trim(substr($value, strpos($value,',')),',');
}
}
echo checkstr($value);
?>
回答by Naftali aka Neal
you can do:
你可以做:
$arr = explode(',', $yyyyy);
unset($arr[0]);
echo implode($arr);
回答by TarranJones
Regex is generally expensive and i wouldn't recommend it for something as simple as this. Using explode and limiting it to 2 will probably result in the same execution time as using str_pos but you wouldn't have to do anything else to generate the required string as its stored in the second index.
正则表达式通常很昂贵,我不会推荐它用于像这样简单的事情。使用爆炸并将其限制为 2 可能会导致与使用 str_pos 相同的执行时间,但您无需执行任何其他操作即可生成所需的字符串,因为它存储在第二个索引中。
//simple answer
$str = explode(',', $yyyyy,2)[1];
OR
或者
//better
$arr = explode(',', $yyyyy,2);
$str = isset($arr[1]) ? $arr[1] : '';