C语言 C：用整数扫描数组
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C: Scan array with Integers
提问by user3027313
How to I scan the values of an array? Like:
如何扫描数组的值？喜欢：
Input: 3 4 5 6 7
What I want:- ar[5] = {3, 4, 5, 6, 7};
It sounds easy, but I'm stuck there. Can anyone help?
这听起来很容易，但我被困在那里。任何人都可以帮忙吗？
回答by tdashago
You can read it as you were reading five integers one after the other:
您可以像阅读五个整数一样阅读它：
for (i = 0; i < 5; i++)
scanf("%d", &array[i]);
So you can input 3 4 5 6 7normally.
这样就可以3 4 5 6 7正常输入了。
回答by Survaf93
All above are valid answers, you could also use dynamically allocated array if you don't know how many elements there is. There's a lot of different versions such as increasing the array size by 1 with each new element or inputing the size at the start...
以上都是有效的答案，如果您不知道有多少个元素，您也可以使用动态分配的数组。有很多不同的版本，例如每个新元素将数组大小增加 1 或在开始时输入大小......
#include<stdio.h>
#include<stdlib.h>
int main(){
int *ar, i, j, h;
scanf("%d", &i); // Input the size of an array
ar = (int*)malloc(sizeof(int)*i); // allocate the memory for your array
for(j = 0; j < i; j++){
scanf("%d", &h);
*(ar+j) = h;
}
for(j = 0; j < i; j++) printf("%d\n", ar[j]);
free(ar);
return 0;
}
And here's an example where you increase the size by 1 with each new element using realloc();. For this example lets say you input numbers until you enter -1.
这是一个示例，其中每个新元素使用realloc();. 对于此示例，假设您输入数字，直到输入 -1。
#include<stdio.h>
#include<stdlib.h>
int main(){
int *ar, i, s = 1;
ar = (int*)malloc(sizeof(int));
do{
scanf("%d", &i);
if(i == -1) break;
ar[s-1] = i;
realloc(ar, ++s);
}while(1);
for(i = 0; i < s - 1; i++) printf("%d\n", ar[i]);
free(ar);
return 0;
}
Very important thing with dynamically allocated arrays is that you need to free the memory using free();before you exit the program.
动态分配的数组非常重要的一点是，您需要free();在退出程序之前释放内存。
回答by nrofis
You need to declare the array size before (recommended with #define), that mean you need to know the size of the input before.
您需要在之前声明数组大小（建议使用#define），这意味着您需要事先知道输入的大小。
#define LEN 5
void main()
{
int arr[LEN];
for (i =0; i < LEN; i++)
scanf("%d", &arr[i]);
}
If you want to cearte an array dynamically you must use pointers (with malloc and realloc).
如果你想动态地激活一个数组，你必须使用指针（使用 malloc 和 realloc）。
void main()
{
int* arr = (int*) malloc(0);
int size = 0;
int val;
for (size = 0; scanf("%d", &val) != EOF; size++)
{
arr = (int*) realloc(arr, size + 1);
arr[size] = val;
}
free(arr);
}
