Bash 脚本捕获输出到终端
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Bash script capturing output to terminal
提问by JDS
I want to capture into my bash script (in a variable) the output of some command that prints its output to terminal. I have tried the following:
我想将某些命令的输出捕获到我的 bash 脚本中（在一个变量中），该命令将其输出打印到终端。我尝试了以下方法：
TEST_OUT=`the_command ARG1` #Nope
#Putting the line "the_command ARG1" into a separate script, testing2.sh,
TEST_OUT=$(./testing2.sh) #Nope
testing2.sh
TEST_OUT=$? #Nope
I am 100% sure that when I run...
我100%确定当我跑步时...
> the_command ARG1
...in a terminal, it prints to the terminal exactly the information I want to capture.
...在终端中，它会准确地向终端打印我想要捕获的信息。
Thank you for any help!
感谢您的任何帮助！
回答by Shawn Chin
If the output is being sent to stderr, you'll need to redirect that to stdout before it can be capture in your var. Try:
如果输出被发送到 stderr，则需要将其重定向到 stdout，然后才能在 var 中捕获它。尝试：
TEST_OUT=$(the_command ARG1 2>&1)
