Python 类型错误：“int”对象不支持项目分配
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TypeError: 'int' object does not support item assignment
提问by Ris
Why do I get this error?
为什么我会收到这个错误？
a[k] = q % b
TypeError: 'int' object does not support item assignment
Code:
代码：
def algorithmone(n,b,a):
assert(b > 1)
q = n
k = 0
while q != 0:
a[k] = q % b
q = q / b
++k
return k
print (algorithmone(5,233,676))
print (algorithmone(11,233,676))
print (algorithmone(3,1001,94))
print (algorithmone(111,1201,121))
采纳答案by mgilson
You're passing an integer to your function as a. You then try to assign to it as: a[k] = ...but that doesn't work since ais a scalar...
您将一个整数作为a. 然后您尝试将其分配为： a[k] = ...但这不起作用，因为它a是一个标量......
It's the same thing as if you had tried:
这与您尝试过的事情相同：
50[42] = 7
That statement doesn't make much sense and python would yell at you the same way (presumably).
那句话没有多大意义，python 会以同样的方式对你大喊大叫（大概）。
Also, ++kisn't doing what you think it does -- it's parsed as (+(+(k)))-- i.e. the bytcode is just UNARY_POSITIVEtwice. What you actually want is something like k += 1
此外，++k没有做你认为它做的事情——它被解析为(+(+(k)))——即字节码只是UNARY_POSITIVE两次。你真正想要的是k += 1
Finally, be careful with statements like:
最后，请注意以下语句：
q = q / b
The parenthesis you use with print imply that you want to use this on python3.x at some point. but, x/ybehaves differently on python3.x than it does on python2.x. Looking at the algorithm, I'm guessing you want integer division(since you check q != 0which would be hard to satisfy with floats). If that's the case, you should consider using:
与 print 一起使用的括号暗示您希望在某个时候在 python3.x 上使用它。但是，x/y在 python3.x 上的行为与在 python2.x 上的行为不同。看看算法，我猜你想要整数除法（因为你检查q != 0哪个很难满足浮点数）。如果是这种情况，您应该考虑使用：
q = q // b
which performs integer division on both python2.x and python3.x.
它对 python2.x 和 python3.x 执行整数除法。
