将此json字符串解析为字符串数组c#
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Parse this json string to string array c#
提问by mdc
Feels like there is a one-two row solution for what I want to do: Parse a string like this:
感觉就像我想做的事情有一个一两行的解决方案：解析这样的字符串：
"{\"postalcode\":\"12345\",\"postalcity\":\"SOME-CITY\",\"country\":\"UK\",\"box\":false}"
Into something like this:
变成这样：
string[] result = { "12345", "SOME-CITY", "UK", "false" };
Whats the simplest way to do this?
什么是最简单的方法来做到这一点？
采纳答案by L.B
string json = "{\"postalcode\":\"12345\",\"postalcity\":\"SOME-CITY\",\"country\":\"UK\",\"box\":false}";
var dict = new JavaScriptSerializer().Deserialize<Dictionary<string,object>>(json);
var postalCode = dict["postalcode"];
//Array is also possible
string[] result = dict.Select(kv => kv.Value.ToString()).ToArray();
回答by James
You could use JavaScriptSerializerto serialize the json into a dynamicobject which would allow you to access the properties via name e.g.
您可以使用JavaScriptSerializer将 json 序列化为一个dynamic对象，该对象将允许您通过名称访问属性，例如
var address = new JavaScriptSerializer().Deserialize<dynamic>(json);
Console.WriteLine(address["postalcode"]);
回答by VRC
You could also use newtonsoft : http://james.newtonking.com/pages/json-net.aspx
您也可以使用 newtonsoft ：http://james.newtonking.com/pages/json-net.aspx
string json = @"{
""Name"": ""Apple"",
""Expiry"": new Date(1230422400000),
""Price"": 3.99,
""Sizes"": [
""Small"",
""Medium"",
""Large""
]
}";
JObject o = JObject.Parse(json);
string name = (string)o["Name"];
// Apple
JArray sizes = (JArray)o["Sizes"];
string smallest = (string)sizes[0];
// Small
I found another related post : JSON to string array in C#
Lib : http://msdn.microsoft.com/en-us/library/system.web.script.serialization.javascriptserializer.aspx
我发现了另一个相关的帖子：JSON to string array in C#
Lib：http: //msdn.microsoft.com/en-us/library/system.web.script.serialization.javascriptserializer.aspx
回答by Sina Iravanian
It looks like your input string is a JSON string, for which you can use a JSON deserializer if you want. If not you can use regular-expression along with named-groups as the following:
看起来您的输入字符串是一个 JSON 字符串，如果需要，您可以使用 JSON 反序列化器。如果没有，您可以将正则表达式与命名组一起使用，如下所示：
List<string> values = new List<string>();
List<string> keys= new List<string>();
string pattern = @"\""(?<key>[^\""]+)\""\:\""?(?<value>[^\"",}]+)\""?\,?";
foreach(Match m in Regex.Matches(input, pattern))
{
if (m.Success)
{
values.Add(m.Groups["value"].Value);
keys.Add(m.Groups["key"].Value);
}
}
var result = values.ToArray();
Named groups in regular-expression are indicated by (?<group-name>pattern). In the above pattern we have two named groups: key, and valuewhich can be grabbed from the Matchobject using the Groupsindexer.
正则表达式中的命名组由 表示(?<group-name>pattern)。在上面的模式中，我们有两个命名组：key, 和value可以Match使用Groups索引器从对象中抓取。
