xcode iPhone URL 编码问题

iPhone URL encoding Problem

提问by gabaum10

Have a slight problem. Trying to post XML to a server. To do this, I have to encode the XML string in URL format.

有一点小问题。尝试将 XML 发布到服务器。为此，我必须以 URL 格式对 XML 字符串进行编码。

NSString *encodedString = [NSString stringWithFormat:@"xmlValue=%@",[post stringByAddingPercentEscapesUsingEncoding: NSASCIIStringEncoding]];

That's what I have and it works for all the characters EXCEPT the '='. This does not get converted to %3D. Has anyone else ever had this problem before? Am I specifying the wrong encoding type? I have tried "NSUTF8StringEncoding" as well.

这就是我所拥有的，它适用于除“=”之外的所有字符。这不会转换为 %3D。有没有其他人遇到过这个问题？我是否指定了错误的编码类型？我也试过“NSUTF8StringEncoding”。

This is a little piece of the XML string:

这是 XML 字符串的一小部分：

@"<xml-service application=\"broadcast\" type=\"REQUEST\"><identity token=\"xxxxxxxx\".....

Any help would be appreciated! Thanks

任何帮助，将不胜感激！谢谢

回答by Ben

This should solve your problem:

这应该可以解决您的问题：

  NSString * encodedString = (NSString *)CFURLCreateStringByAddingPercentEscapes(
    NULL,
    (CFStringRef)unencodedString,
    NULL,
    (CFStringRef)@"!*'();:@&=+$,/?%#[]",
    kCFStringEncodingUTF8 );

Source

来源

回答by Nishant

You can try this. I found this helpful.

你可以试试这个。我发现这很有帮助。

NSString *sampleUrl = @"http://www.google.com/search.jsp?params=Java Developer";
NSString* encodedUrl = [sampleUrl stringByAddingPercentEscapesUsingEncoding:
 NSASCIIStringEncoding];