如何在 SQL PIVOT 中按顺序排序
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How to ORDER BY in SQL PIVOT
提问by greener
I currently have this query using PIVOT generating a table like this:
我目前使用 PIVOT 生成如下表的查询：
USER | DEC | NOV | OCT
---------------------------------
bob | 3 | 5 | 2
jon | 7 | 0 | 1
tim | 4 | 2 | 6
What I would like to do but it looks like a stretch is to ORDER BYthe results by the DECvalue descending.
我想要做的，但它看起来像一个延伸ORDER BY的DEC价值下降的结果。
This is the query:
这是查询：
with Mth (st, nd) as (
select DATEADD (M, datediff (m, 0,'2012-09-01'), 0),
DATEADD (M, DATEDIFF (m, 0, '2012-09-01') + 1, 0)
union all
select DATEADD (m, 1, st),
DATEADD (m, 1, nd)
from Mth
where nd <= DATEADD (m, datediff (m, 0, getdate()), 0)
)
select *
from
(
select MONTH(Mth.st) Month,
U.USER,
COUNT(S.QRY_ID) Searches
FROM Mth
LEFT JOIN SEARCHES S
on Mth.st <= S.CREATED
and Mth.nd > S.CREATED
LEFT JOIN MEMBERS U
on U.AID = S.AID
GROUP BY YEAR(Mth.st), MONTH(Mth.st), U.HOLDER_LOGIN
) src
pivot
(
sum(searches)
for month in ([12],[11],[10])
) piv
Doing piv ORDER BY piv.Searchesgives an error so is it possible to specify the column?
这样做piv ORDER BY piv.Searches会出错，所以可以指定列吗？
回答by Mahmoud Gamal
Try this:
尝试这个：
with Mth (st, nd) as (
select DATEADD (M, datediff (m, 0,'2012-09-01'), 0),
DATEADD (M, DATEDIFF (m, 0, '2012-09-01') + 1, 0)
union all
select DATEADD (m, 1, st),
DATEADD (m, 1, nd)
from Mth
where nd <= DATEADD (m, datediff (m, 0, getdate()), 0)
), Pivoted
AS
(
select *
from
(
select MONTH(Mth.st) Month,
U.USER,
COUNT(S.QRY_ID) Searches
FROM Mth
LEFT JOIN SEARCHES S
on Mth.st <= S.CREATED
and Mth.nd > S.CREATED
LEFT JOIN MEMBERS U
on U.AID = S.AID
GROUP BY YEAR(Mth.st), MONTH(Mth.st), U.HOLDER_LOGIN
) src
pivot
(
sum(searches)
for month in ([12],[11],[10])
) piv
)
SELECT *
FROM Pivoted
ORDER BY Dec
