如何对数字字符串的python列表进行排序
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How to sort python list of strings of numbers
提问by vaibhav jain
I am trying to sort list of strings containing numbers
我正在尝试对包含数字的字符串列表进行排序
a = ["1099.0","9049.0"]
a.sort()
a
['1099.0', '9049.0']
b = ["949.0","1099.0"]
b.sort()
b
['1099.0', '949.0']
a
['1099.0', '9049.0']
But list bis sorting and not list a
但是列表b是排序而不是列表a
采纳答案by arshajii
You want to sort based on the floatvalues (not string values), so try:
您想根据float值（而不是字符串值）进行排序，请尝试：
>>> b = ["949.0","1099.0"]
>>> b.sort(key=float)
>>> b
['949.0', '1099.0']
回答by Markon
They are both sorted. '1' comes before '9'. Look at here: Ascii table
它们都是排序的。“1”在“9”之前。看这里： Ascii 表
回答by xlharambe
Convert them to intor floator even decimal(since it has trailing numbers)
将它们转换为int或float甚至decimal（因为它有尾随数字）
>>> b = [float(x) for x in b]
>>> b.sort()
>>> b
[949.0, 1099.0]
回答by Samuele Mattiuzzo
回答by Borja_042
In case anybody is dealing with numbers and extensions such as 0.png, 1.png, 10.png, 2.png... We need to retrieve and sort the characters before the extension since this extension does not let us to convert the names to floats:
如果有人正在处理数字和扩展名，例如 0.png、1.png、10.png、2.png...我们需要在扩展名之前检索和排序字符，因为这个扩展名不允许我们转换浮动名称：
sorted(list, key=lambda x: float(x[:-4]))
